用星号替换不礼貌的单词，星号的数量与不礼貌单词中的字母数量相匹配 - Replace rude words for asterisks and have the number of asterisks match the number of letters in the rude words

Replace rude words for asterisks and have the number of asterisks match the number of letters in the rude words

我有以下代码，它正在从字符串中过滤出粗鲁的单词，并将它们替换为askerisks，但是我希望askerisks的数量等于粗鲁单词中的字母数量。例如，如果"ass"这个词被删除，那么它将被三个askerisk所取代。我如何修改这段代码来实现这一点?谢谢。

$naughtyWords = array("ahole","anus","ash0le","ash0les","asholes","ass"); //etc
foreach ($naughtyWords as &$word) {
    $word = ' '.$word.' ';
}
$string = str_replace($naughtyWords, " **** ", ' '.$string.' ');

试试这个:

$naughty_words = array('ahole', 'anus', 'ash0le', 'ash0les', 'asholes', 'ass');
$string = 'classical music ass dirty ass. molass';
foreach ($naughty_words as $naughty_word) {
    $string = preg_replace_callback('#'b' . $naughty_word . ''b#i', function($naughty_word) {return str_repeat('*', strlen($naughty_word[0]));}, $string);
}

尝试:

$naughtyWords = array("ahole","anus","ash0le","ash0les","asholes","ass"); //etc
foreach ($naughtyWords as $word) {
    $replacement = str_repeat('*', strlen($word));
    $string = str_replace(' '.$word.' ', $replacement, $string);
}