这是我的认证控制器
class AuthController extends Controller
{
public function actionLogin()
{
$model = new LoginForm;
$post = Yii::app()->request->getPost('LoginForm');
// If form is submitted
if($post) {
$identity = new UserIdentity($post['username'], $post['password']);
if($identity->authenticate()) { // loop enters but could not get id
echo Yii::app()->user->id;
echo Yii::app()->user->getId();
} else {
echo 'failed';
}
//exit;
}
$this->render('login', array('model' => $model));
}
}
这是我的UserIdentity.php
class UserIdentity extends CUserIdentity
{
private $_id;
public function authenticate()
{
$user = SchLogins::model()->findByAttributes(array('username' => $this->username));
if(is_null($user)) {
$this->errorCode=self::ERROR_USERNAME_INVALID;
} else if($user->password != $this->password) {
$this->errorCode=self::ERROR_PASSWORD_INVALID;
} else {
$this->_id = $user->id;
$this->errorCode=self::ERROR_NONE;
}
return !$this->errorCode;
}
public function getId()
{
return $this->_id;
}
}
在上面的代码中，我在获取用户id(即)Yii::app()->user->getId();时遇到问题，这没有返回任何东西，我做了上面的代码
您正在创建LoginForm实例$model，但您从未使用它实际登录。如果您使用的是标准的LoginForm模型，那么它就是与UserIdentity类交互的。应该是这样:
if($post) {
$model->attributes = $_POST['LoginForm'];
if ($model->validate() && $model->login()) { // loop enters but could not get id
echo Yii::app()->user->id;
echo Yii::app()->user->getId();
} else {
echo 'failed';
}
//exit;
}
如果你看一下LoginForm的login()函数，你会看到它调用Yii::app()->user->login($this->_identity,$duration);，这实际上是设置Yii::app()->user的方法被跳过。