在弹出窗口中获取php中对应行的值


get the values in the popup window for corresponding row in php

<table>
    <tbody align="center" style="font-family:inherit">
        <?php
        $resultbooked ="SELECT *,b1.paid_amount as sub_total FROM booking_details b1,payment_history b2 WHERE b1.id='".$bookingid."' AND b2.booking_id='".$bookingid."'";
        $exe= mysql_query($resultbooked);
        $i=0;
        while($bookedrow= mysql_fetch_array($exe))
        {
        $i++;?>
        <tr>
            <td style="display:none;"><?php echo $bookedrow['id']; ?></td>
            <td><?php echo $i;?></td>
            <td>
                <?php $date_format=$bookedrow['present_date'];
                echo $chng_date=date('d-m-Y',strtotime($date_format));?>
            </td>
            <td>
                <?php echo $bookedrow['paid_amount'];
                $total=$bookedrow['sub_total'];?>
            </td>
            <td>
              <p class="current_pay" booking_id="<?php echo $bookingid;?>">
                <p class="current_pay" pay_id="<?php echo $bookedrow['id'];?>"><span class="icon-print" style="cursor:pointer;"></span></p>
                <?php
                }?>
            </td>
        </tr>
    </tbody>
</table>
<div id="payment_details<?php echo $bookedrow['id']; ?>" class="show_current_payment" style="display:none;margin: 0 auto; width: 60%; background:#FC9;">
    <button onclick="printbill()" class="no-print button sButton bOlive">Print</button>
</div>

我正试图从select查询到div id-payment_details但我无法获得$bookedrow['id']$bookedrow['id']值?我怎么能得到那个值在那个id值!!

如果$bookedrow["id"]总是表中的第一个,这似乎是可行的。它获取页面中第一个td元素中的文本(因此在php循环之后,当文本在那里回显时使用此方法),并将该值添加到隐藏的输入值中。

 $("#id-payment_details").val($("td:first").text());