我在php中遇到了问题。我尝试显示所有数据，然后将它们放在嵌套循环中。但第二个循环仅返回 null。我不知道我做错了什么。
<?php
ini_set('max_execution_time', 36000);
$con=mysqli_connect("localhost","root","XXX","YahooFin");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"show tables from yahooFin where not tables_in_yahooFin = 'nasdaqCompanyList' and not tables_in_yahooFin = 'companylist'");
while($row = mysqli_fetch_array($result)) {
$result2 = mysqli_query($con, "select * from ".$row['Tables_in_yahoofin']." where entry_date = '2013-06-03'order by entry_date asc limit 1");
while ($row2 = mysqli_fetch_array($result2)); //<== This line gives me null
{
var_dump( $row2);
echo "<br>";
}
}
var_dump($row);
mysqli_close($con);
?>
有一个
额外的;分号，不应该在你的循环之后出现
while ($row2 = mysqli_fetch_array($result2)); //<== This line gives me null
//^ remove this one
此外，您可能有一个拼写错误tables_in_yahooFin在第一个查询中使用Tables_in_yahoofin而在第二个查询中使用。