我正在使用Laravel 5.3并且在通过hasMany
关系保存时遇到问题。
我有表employee和activity,它们具有一对多关系,即每个员工将执行许多活动。
当我使用associate()
添加针对员工的活动时,它发送给我一个错误:
BadMethodCallException in Builder.php line 2440:
Call to undefined method Illuminate'Database'Query'Builder::associate()
下面是DB结构和代码:
数据库结构:
employee (1st table)
– employee_id
– employee_name
- created_at
- updated_at
activity (2nd table)
– activity_id
– activity_name
- created_at
- updated_at
employee_activity (pivot table)
– employee_activity_employee_id
– employee_activity_activity_id
Model Class Employee:
class Employee extends Model
{
protected $table = 'employee';
protected $primaryKey = 'employee_id';
public function activity() {
return $this->hasMany('App'Models'Activity', 'employee_activity', 'employee_activity_employee_id', 'employee_id');
}
}
模范班级活动:
class Activity extends Model
{
protected $table = 'activity';
protected $primaryKey = 'activity_id';
public function employee() {
return $this->belongsTo('App'Models'Employee', 'employee_activity', 'employee_activity_activity_id' ,'activity_id');
}
}
控制器:
public function EmployeeActivityAssociation()
{
$employee_id = Input::get('employee_id');
$activity_ids = Input::get('activity_id'); // This is an array of activities
$employee = Employee::find($employee_id);
if (!empty($employee)) {
//Adding activity under the employee
foreach ($activity_ids as $id) {
$activity = Activity::find($id);
$employee->activity()->associate($activity);
$employee->save();
}
return 'Activities asscoiated to employee';
}
else {
return 'Employee not found';
}
}
我的关系定义不正确吗?
您的关系没有正确定义。通过查看表结构,它应该是many-to-many
关系。
Model Class Employee:
public function activity() {
return $this->belongsToMany('App'Models'Activity', 'employee_activity', 'employee_activity_employee_id', 'employee_id');
}
模范班级活动:
public function employee() {
return $this->belongsToMany('App'Models'Employee', 'employee_activity', 'employee_activity_activity_id' ,'activity_id');
}
所以你的控制器应该是:
public function EmployeeActivityAssociation()
{
$employee_id = Input::get('employee_id');
$activity_ids = Input::get('activity_id'); // This is an array of activities
$employee = Employee::find($employee_id);
if (!empty($employee)) {
$employee->activity()->attach($activity_ids);
return 'Activities asscoiated to employee';
}
else {
return 'Employee not found';
}
}
如果你想坚持一对多的关系,那么你必须改变你的表模式:
删除表employee_activity
表,在活动表中添加列employee_id
,然后定义一对多关系
使用多对多方案,并且在迁移时,将字段'activity_id'定义为'employee_activity'表上的'唯一':
$table->unsignedInteger('employe_id');
$table->unsignedInteger('activity_id')->unique();
通过这种方式,您可以在'employee_activity'表上只注册与一个雇员相关联的一个活动,而一个雇员可以与多个活动相关联。