Laravel单元测试，如何“查看”数据库;软删除行 - Laravel Unit Testing, how to "seeInDatabase" soft deleted row?

我正在进行一个小单元测试，其中我软删除了一行。为了标记测试成功，我必须用

找到那一行

给定ID和
deleted_at列不应为空。

我可以满足第一个条件-因为显然我知道ID。

不幸的是，我不知道如何告诉seeInDatabase方法，我希望deleted_at 不是 null:

$this->seeInDatabase(
       'diary_note_categories',
       [
           'id' => 'a7e35ad0-6f00-4f88-b953-f498797042fc',
           'deleted_at' => null // should be is not null, like <> or != or whatever
       ]
 );

提示吗?

'deleted_at <>' => null break

'deleted_at' => ['!=' => null] 也有断点

我这样做了:

$this->seeInDatabase('diary_note...',['id' => 'a7e35ad0'])
->notSeeInDatabase('diary_note...',['id' => 'a7e35ad0','deleted_at'=>null]);

我检查了两步

我检查是否有一个记录与我们的id在表
我检查是否没有记录与我们的id和deleted_at = null在表

目前还不可能。seeInDatabase和notSeeInDatabase都只是将数组直接传递给查询生成器的where方法，当传递数组时，它不理解如何处理=以外的任何东西。

https://github.com/laravel/framework/blob/2b4b3e3084d3c467f8dfaf7ce5a6dc466068b47d/src/Illuminate/Database/Query/Builder.php L452

public function where($column, $operator = null, $value = null, $boolean = 'and')
{
    // If the column is an array, we will assume it is an array of key-value pairs
    // and can add them each as a where clause. We will maintain the boolean we
    // received when the method was called and pass it into the nested where.
    if (is_array($column)) {
        return $this->whereNested(function ($query) use ($column) {
            foreach ($column as $key => $value) {
                $query->where($key, '=', $value);
            }
        }, $boolean);
    }
    // ...
}

选项1 -将以下代码添加到您的TestCase类中，您可以从

扩展测试用例

要点:https://gist.github.com/EspadaV8/73c9b311eee96b8e8a03

<?php
/**
 * Assert that a given where condition does not matches a soft deleted record
 *
 * @param  string $table
 * @param  array  $data
 * @param  string $connection
 * @return $this
 */
protected function seeIsNotSoftDeletedInDatabase($table, array $data, $connection = null)
{
    $database = $this->app->make('db');
    $connection = $connection ?: $database->getDefaultConnection();
    $count = $database->connection($connection)
        ->table($table)
        ->where($data)
        ->whereNull('deleted_at')
        ->count();
    $this->assertGreaterThan(0, $count, sprintf(
        'Found unexpected records in database table [%s] that matched attributes [%s].', $table, json_encode($data)
    ));
    return $this;
}
/**
 * Assert that a given where condition matches a soft deleted record
 *
 * @param  string $table
 * @param  array  $data
 * @param  string $connection
 * @return $this
 */
protected function seeIsSoftDeletedInDatabase($table, array $data, $connection = null)
{
    $database = $this->app->make('db');
    $connection = $connection ?: $database->getDefaultConnection();
    $count = $database->connection($connection)
        ->table($table)
        ->where($data)
        ->whereNotNull('deleted_at')
        ->count();
    $this->assertGreaterThan(0, $count, sprintf(
        'Found unexpected records in database table [%s] that matched attributes [%s].', $table, json_encode($data)
    ));
    return $this;
}

选项2 -安装以下编译器包

这个composer包与上面的代码完全相同，但是是为composer打包的。

composer require kirkbater/soft-deletes

然后在特定的测试类中使用它:

<?php
use Kirkbater'Testing'SoftDeletes;
class MyTestClass extends TestClass {
    use SoftDeletes;
}

这是一个老问题，但是对于那些使用最新版本的Laravel(5.4及以上)的人来说，现在有一个assertSoftDeleted断言:

所以原来问题的答案现在是:

$this->assertSoftDeleted('diary_note_categories', [
    'id' => 'a7e35ad0-6f00-4f88-b953-f498797042fc'
]);

断言给定的记录已被删除(Laravel 5.4及以上)。

assertSoftDeleted(string|Model $table, array $data = []， string|null $connection = null)

id:

的示例

$this->assertSoftDeleted('table_name', ['id'='value'])

model:

示例

$user = User::factory()->create();
$user->delete();
$this->assertSoftDeleted($user);

我在Laravel 6中使用过

$this->assertDatabaseMissing('stores', [
'id' => $test_data['store']->id, 'deleted_at' => null
]);
$this->assertDatabaseHas('stores', ['id' => $id]);

没有测试，但试着这样做:

$this->seeInDatabase(
       'diary_note_categories',
       [
           'id' => 'a7e35ad0-6f00-4f88-b953-f498797042fc',
           'deleted_at' => ['deleted_at' ,'!=', null ] // should be is not null, like <> or != or whatever
       ]
 );