高级路由Laravel


Advanced Routing Laravel

我目前有一个简单的CRUD应用程序内置在LaravelBooksdatabase相互作用。这是我的routes.php文件:

Route::model('book', 'Book');
//Show pages
Route::get('/', 'BookController@index');
Route::get('book/create', 'BookController@create');
Route::get('book/edit/{book}', 'BookController@edit');
Route::get('book/delete/{book}', 'BookController@delete');
Route::get('book/view/{book}', 'BookController@view');
//Handle form submissions
Route::post('create', 'BookController@handleCreate');
Route::post('edit', 'BookController@handleEdit');
Route::post('delete', 'BookController@handleDelete');

然后在我的views文件夹中,我有以下文件:

create.blade.php
edit.blade.php
index.blade.php
layout.blade.php
view.blade.php

ControllerBookController:

class BookController extends BaseController {
    //View page - Shows list of books
    public function index(){
        $books = Book::all();
        //compact()creates array of the books using names as keys
        return View::make('index', compact('books'));
    }
    //Create page - Shows create Form
    public function create(){
        return View::make('create');
    }
    //Logic to add a new book to the DB
    public function handleCreate(){
        $book = new Book;
        $book->book_name = Input::get('name');
        $book->book_desc = Input::get('desc');
        $book->save();
        return Redirect::action('BookController@index');
    }
    //Edit page - Shows edit form and populates with book info
    public function edit(Book $book){
        return View::make('edit', compact('book'));
    }
    //Logic to update an existing book in the DB
    public function handleEdit(){
        $book = Book::findOrFail(Input::get('id'));
        $book->book_name = Input::get('name');
        $book->book_desc = Input::get('desc');
        $book->save();
        return Redirect::action('BookController@index');
    }
    //Delete page
    public function delete(Book $book){
        //Show delete confirmation page
        return View::make('delete', compact('book'));
    }
    public function handleDelete(){
        //Handle delete logic...
        $id = Input::get('book');
        $book = Book::findOrFail($id);  
        $book->delete();
        return Redirect::action('BookController@index');
    }
    //View 
    public function view(Book $book){
        return View::make('view', compact('book'));
    }
}

我的问题是,如果我将不同的views嵌套在名为books的子文件夹中,我如何修改我的路由?我尝试创建一个名为books的文件夹,并将views粘贴到其中,当我运行应用程序时,它说它找不到视图。

查看子文件夹

您可以简单地使用点语法在views文件夹中向下导航文件夹结构。以索引视图为例,如果你想让它驻留在views'books中,你可以这样做:

public function index(){
    $books = Book::all();
    return View::make('books.index', compact('books'));
}

就是这样!Laravel让它非常简单。

如果我们想要更深入一些,那么在books下的另一个子文件夹travel会怎样呢?也就是views'books'travel:

public function index(){
    $books = Book::all();
    return View::make('books.travel.index', compact('books'));
}


<标题> 资源路由

同样值得注意的是,Laravel使路由到像BookController这样的RESTful控制器非常容易使用Route::resource。所有映射到方法的GET和POST请求都已经为您完成了。点击这里查看:http://laravel.com/docs/controllers#resource-controllers