我有两个class
class Pet {
public $pet = null;
public function setPet(){}
public function getPet(){}
}
和
class B {
public $cat = 'cat';
public $dog = 'bog';
public function cat()
{
$pet = new Pet();
$pet->pet = $this->cat;
}
public function dog()
{
$pet = new Pet();
$pet->pet= $this->dog;
}
}
我可以接这个吗:
$pet = new Pet();
$pet->setPet()->dog();
$pet->getPet(); //dog
我不相信你能。可以让类B扩展Pet。这将允许您从类Pet调用函数。仔细阅读对象继承，这可能会有所帮助!http://php.net/manual/en/language.oop5.inheritance.php
您可以简单地在类B上扩展类Pet以调用来自Pet类的函数。因此类B继承了Pet的函数。
Class B extends Pet {
// class B functions here...
}
当我在这里写下我的代码时，我笑了。
<?php
class Pet {
public $name;
public function setName($string) {
$this->name = $string;
}
public function getName() {
return $this->name;
}
}
class Dog extends Pet {
public function bark() {
echo "Arf arf!";
}
}
class Cat extends Pet {
public function meow() {
echo "Meoooww~ purrr~";
}
}
$dog = new Dog();
$dog->setName("Jacob");
$dog->bark(); //Arf arf!
echo "Good job, ".$dog->getName()."!"; //Good job, Jacob!
?>
先生，你不能用->dog()调用$pet->setPet()->dog()，因为setPet()是一个函数而不是一个对象。就像他们说的，处理代码的正确方法是将其扩展为一个超类，并声明一个Dog类作为子类。
My variant
class Pet {
public $pet = null;
public function setPet($pet = null)
{
if (is_null($pet)) {
return new B($this);
} else {
$this->pet = $pet;
return $this;
}
}
public function getPet()
{
return $this->pet;
}
}
class B {
protected $pet = null;
protected $cat = 'cat';
protected $dog = 'bog';
public function __construct(Pet $pet)
{
$this->pet = $pet;
}
public function cat()
{
$this->pet->setPet($this->cat);
return $this->pet;
}
public function dog()
{
$this->pet->setPet($this->dog);
return $this->pet;
}
}
$pet = new Pet();
$pet->setPet()->cat();
var_dump($pet->getPet());