Php下拉和日期功能


Php Drop Down and Date function

我是php新手。我正在开发一个表单与以下代码:

<td>Severity:</td>
<td>
    <?php $dbc = mysql_connect('localhost', 'root', ''); // root connection
    mysql_select_db('ticket', $dbc); // db selection
    $query = "SELECT id, severity FROM severity" ; // retrieving value from table severity in db
    $result = mysql_query($query, $dbc); // 
    echo'<select name="sever">';
    echo '<option value="Default"> Please Select Severity </option>';
    while($row = mysql_fetch_assoc( $result ))
    {
        echo '<option value="'.$row['id'].'">' . $row['severity'] . '</option>';
    }
    echo '</select>';
?>
</td>

在数据库中,我创建了3个严重性级别,值如下:

Table Severity (ID, Severity, Hours)值(1, 'Critical', '12'),(2, 'Major', '24'),(3, 'Minor', '36');

我有一个日期函数,格式为

<td> Expected Completed Date: </td>
        <td> <input name="exc_date" style="width:150px" type="text" /> </td>

一旦我选择严重性,我希望预期完成的日期将根据严重性的选择自动生成。

我有点模棱两可,我需要如何在预期完成日期的形式生成php代码。

请帮助我,并提前感谢您的建议。

纯Javascript解决方案(不含jQuery)

jsFiddle演示

使用data-hours属性输出每个选项的小时数:

echo '<option data-hours="'.$row['hours'].'" value="'.$row['id'].'">' . $row['severity'] . '</option>';

还提供<select>server的ID,然后使用Javascript进行更改:

window.onload = function(){
    document.getElementById("server").onchange = function(){
        var timeObj = document.getElementById("exc_date");
        if(this.value != 'Default'){
            var hours = this.options[this.selectedIndex].getAttribute('data-hours');
            var now = new Date();
            now.setHours(now.getHours() + (hours*1));
            var nowStr = now.getDate() + "/" + (now.getMonth()+1) + "/" + now.getFullYear();
            timeObj.value = hours + " hours, " + nowStr; 
        } else {
            timeObj.value = '';   
        }
    };
};

将ID为exc_date的元素更新为小时数。

将PHP部分改为

<td>Severity:</td>
<td>
    <?php $dbc = mysql_connect('localhost', 'root', ''); // root connection
    mysql_select_db('ticket', $dbc); // db selection
    $query = "SELECT id, severity, hours FROM severity" ; // retrieving value from table severity in db
    $result = mysql_query($query, $dbc); // 
    echo'<select name="sever">';
    echo '<option value="Default"> Please Select Severity </option>';
    while($row = mysql_fetch_assoc( $result ))
    {
        echo '<option value="'.$row['id'].'" data-hours="'.$row['hours'].'">' 
             . $row['severity'] . '</option>';
    }
    echo '</select>';
?>
</td>

并添加JavaScript - http://jsfiddle.net/8YCwb/.