$str = "PHP is a server-side {{scripting language}} designed for {{web development}} but also used as a general-purpose programming language";
$search = 'language';
$replace = 'english';
$new_str = str_replace($search, $replace, $str);
在上面的代码中,我们如何排除 {{ ... }} 中的字符串。 这样输出应该是
"PHP is a server-side {{scripting language}} designed for {{web development}} but also used as a general-purpose programming english"
使用 preg_replace()
而不是 str_replace()
:
$pattern = sprintf('/{{[^}]+}}(*SKIP)(*F)|%s/', preg_quote($search, '/'));
$new_str = preg_replace($pattern, $replace, $str);
{{[^}]+}}
匹配{{...}}
块内的内容,(*SKIP)(*F)
跳过它,%s
(用转义的搜索字符串替换(匹配所需的单词。
演示