从一个页面到另一个页面获取图像变量

好吧，我搜索了很多，但没有任何帮助。我有这样一个表单:

<form action="update.php" id="Form2" method="POST" enctype="multipart/form-data" class="c">
  <div align="center">
    <?php echo "Updating information about Patient ".$row["name"]; ?>
    <table class="imagetable" border="1" cellspacing="3"  align="center">
      <th>Personal Informations</th>
      <th>Test Results</th>
      <tr><td>Name<br>
          <input type="text" class="large-fld" name="name" placeholder="Patient Name" value="<?php echo $row['name'];?>"/></td>
        <td>Remarcs:<br>
          <textarea type="text" cols="40" rows="5" class="large-fld"  name="remarcs" placeholder="Remarcs"><?php echo $row['remarcs'];?></textarea></td>
      <tr><td>Address<br>
          <input type="text" class="large-fld" name="address" placeholder="Address" value="<?php echo $row['address'];?>"/>
        </td>
        <td>Test<br>  <textarea type="text" cols="40" rows="5" class="large-fld"  name="test_res" placeholder="Test Result"><?php echo $row['test_res'];?></textarea></td></tr>
      </td>
      </tr>
      <tr><td>Phone Number<br>
          <input type="text" class="large-fld" name="phone_num" placeholder="Phone Number" value="<?php echo $row['phone_num'];?>"/>
        </td>
        <th>Files</th>
      </tr>
      <td>Scanned Echo Photo<br>
        <input type="file" class="" name="echo_photo" id="echo_photo" placeholder="Add echo photo" value="<?php echo $row['echo_photo'];?>"/></td>
      <td>Echo Files:<br>
        <input type="file" name="fileToUpload"  value="<?php echo $row['echo_files'];?>"/><br></td>
      </tr></th></table>
    <div class="row" align="center">
      <input type="submit" name="submit" id="btnUploadId" class="large-btn" value="Update" onClick="btnOnClickUpload()">
      <input type="hidden" id="courseIdHidden" value="<?php echo $idd; ?>" /></td></tr>
      </table></div>
</form>

和我不能得到的图像和文件到下一页使用它们来更新表使用php:

$host=""; // Host name 
$username=""; // Mysql username 
$password=""; // Mysql password 
$db_name=""; // Database name 
$tbl_name=""; // Table name 

$id=$_REQUEST['id'];
if (isset ($_POST['name'])) {
  $name = $_POST['name'];
}
if (isset ($_POST['remarcs'])) {
  $remarcs = $_POST['remarcs'];
}
if (isset ($_POST['test_res'])) {
  $test_res = $_POST['test_res'];
}
if (isset ($_POST['address'])) {
  $address = $_POST['address'];
} 
if (isset ($_POST['phone_num'])) {
  $phone = $_POST['phone_num'];
} 
echo $name;
echo $remarcs;
echo $test_res;
echo $address;
echo $phone;

这些变量的Echo都工作得很好如何完成这个任务?请帮助