从输入中按位置从字符串中删除单词 - remove word from string by position from input

remove word from string by position from input

>示例：

输入 = 2

文本 = AA BB 抄送

将成为：aa cc

仓位的输入为 $_POST['仓位']

我有

$words = explode(" ", $_POST['string']);
for ($i=0; $i<count($words); $i++){ 
    echo $words[$i] . " ";
}

$to_remove = 2;
$text = "aa bb cc";
$words = explode(' ', $text);
if(isset($words[$to_remove -1])) unset($words[$to_remove -1]);
$text = implode(' ', $words);

拔

出大枪 REGEX !!

$string = 'aa bb cc dd';
$input = 2;
$regex = $input - 1;
echo preg_replace('#^((?:'S+'s+){'.$regex.'})('S+'s*)#', '$1', $string);

输出：aa cc dd

Foreach 循环往往使其更容易理解 (IMO(。看起来也更干净。

$pos = 2;
$sentence = explode(" ", $_POST['string']);
foreach ($sentence as $index => $word) {
    if ($index != $pos - 1) {
        $result .= $word . ' ';
    }
}
echo $result;

这

听起来像是一个家庭作业问题。不过我会试一试：

法典：

<?php
    $string = trim($_POST['string']);
    $parts = explode(" ", string);
    $newString = "";
    $position = intval($_POST['position']);
    for($a = 0; $a < count($parts); $a++) {
        if($a != $position) { // or $a != ($position - 1) depending on if you passed in zero based position
            $newString = $newString . $parts[$a] . " ";
        }
    }
    $newString = trim($newString);
    echo "Old String: " . $string . "<br />";
    echo "New String: " . $newString;
?>

输出：

Old String: aa bb cc
New String: aa cc

$input = 2;
$words = explode(" ", $_POST['string']);
unset($words[$input-1]);
$words = implode(" ", $words);
echo $words;