PHP和MySQL数据库搜索多个表在同一时间 - PHP and MySQL Database Search Multiple Tables At One Time

我正试图通过ID，名和姓进行表单搜索。我希望用户在搜索字段中键入任何一个，并从数据库中获得结果。

下面是我使用的实际形式:

<form action="form.php" method="post"> 
<input type="text" name="term" />
<input type="submit" value="Submit" /> 
</form>

这里是form。php

<?php
$db_hostname = 'localhost';
$db_username = 'test';
$db_password = 'test';
$db_database = 'test';
// Database Connection String
$con = mysql_connect($db_hostname,$db_username,$db_password);
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db($db_database, $con);
?>
<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8" />
        <title>SpeedZone Data Search</title>
        <style type="text/css">
table { border-collapse:collapse; }
table td, table th { border:1px solid black;padding:5px; }
tr:nth-child(even) {background: #ffffff}
tr:nth-child(odd) {background: #ff0000}
</style>
    </head>
    <body>
<form action="form.php" method="post">  
<input type="text" name="term" />
<input type="submit" value="Search" />  
</form>  
<?php
if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);     
$sql = "SELECT * FROM rcrentals WHERE firstname LIKE '%".$term."%' or lastname LIKE '%".$term."%' or id = ".$term;
$r_query = mysql_query($sql); 
echo "<table border='1' cellpadding='5'>";
echo "<tr> <th>ID</th> <th>First Name</th> <th>Last Name</th> <th>Address</th> <th>City</th> <th>State</th> <th>Zip</th> <th>Phone</th> <th>DL</th> <th>Email</th> <th>Car and Controller</th> <th></th> <th></th></tr>";
// loop through results of database query, displaying them in the table
        while ($row = mysql_fetch_array($r_query)){
                // echo out the contents of each row into a table
                echo "<tr>";
                echo '<td>' . $row['id'] . '</td>';
                echo '<td>' . $row['firstname'] . '</td>';
                echo '<td>' . $row['lastname'] . '</td>';
                echo '<td>' . $row['address'] . '</td>';
                echo '<td>' . $row['city'] . '</td>';
                echo '<td>' . $row['st'] . '</td>';
                echo '<td>' . $row['zip'] . '</td>';
                echo '<td>' . $row['phone'] . '</td>';
                echo '<td>' . $row['dl'] . '</td>';
                echo '<td>' . $row['email'] . '</td>';
                echo '<td>' . $row['carcont'] . '</td>';
                echo '<td><a href="edit.php?id=' . $row['id'] . '">Edit</a></td>';
                // echo '<td><a href="delete.php?id=' . $row['id'] . '">Delete</a></td>';
                echo '<td><a href="delete.php?id=' . $row['id'] . '" onclick="return confirm(''Confirm?'')">Delete</a></td>';
                echo "</tr>"; 
        } 
        // close table>
        echo "</table>"; 
}
?>
    </body>
</html>

我目前有这个:它只搜索ID。我希望能够输入ID，或者名字，或者姓氏，如果可能的话，还可以输入第一个和最后一个。

if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);     
$sql = "SELECT * FROM rcrentals WHERE firstname LIKE '%".$term."%' or lastname LIKE '%".$term."%' or id = ".$term;

我认为有一些事情我需要改变，但我很困惑，已经失去了自己，无法解决它。请帮助。

当您将$term与id进行比较时，需要在其周围加上引号。否则，如果它不是一个数字，你会得到一个语法错误。

$sql = "SELECT * FROM rcrentals WHERE firstname LIKE '%".$term."%' or lastname LIKE '%".$term."%' or id = '".$term."'";

同样，这假定您不使用0作为id。当将数字与字符串进行比较时，字符串被转换为数字，所有非数字字符串被转换为0，并且它们将匹配id。如果有问题，您应该先检查$term是否为数字。如果不是数字，则使用不包含id检查的查询:

$sql = "SELECT * FROM rcrentals WHERE firstname LIKE '%$term%' or lastname LIKE '%$term%'";
if (is_numeric($term)) {
  $sql .= " or id = $term";
}

你的查询看起来很正确。尝试使用大括号分隔OR条件

$sql = "SELECT * FROM rrecals WHERE firstname LIKE '%".$term."%"或(lastname像"%"。术语。美元"%")或(id = " $术语);