我使用这段代码来替换图像，但是图像没有上传到上传文件夹中，但是数据库更新了。我需要替换图像。
<?php
require("header.php");
$patientid = $_POST['patientid'];
$pname = $_POST['pname'];
$fname = $_POST['fname'];
$address = $_POST['address'];
if(!$pname || !$address) {
echo "<center>";
echo "Fillup required fields<br><br>";
echo "</center>";
}
else {
$ran2 = $patientid;
$new_name2 = $ran2."b";
$new_file_name2 = $new_name2."."."jpg";
$path = "./members/".$new_file_name2;
$copied = move_uploaded_file($_FILES['img_name']['tmp_name'], $path);
if ($copied) {
$sql = mysql_query("UPDATE info_store
SET pname='$pname', fname='$fname', address='$address', image1='$new_file_name2'
WHERE patientid='$patientid'");
return true;
}
else {
echo "<center><h3>There are An Errors In Uploading!</h3></center>";
return false;
}
}
?>
请给我一个解决方案。
看这个(替换图片):
你的PHP代码:
<?php
$path = '/my/folder/uploads/';
$row = mysql_fetch_assoc("select source from images where id = X ");
$File_Name_Here = $path . $row['source'];
@unlink( $path. $File_Name_Here );
$output = $path . 'md5(time()).jpg'
copy( $_FILE['image']['tmp_name'] , $output );
?>
请使用函数复制并阅读此文档:
PHP函数:复制
PHP函数:拆开
你的HTML代码:
<form action="" method="post" enctype="multipart/form-data">
...Your fields here...
</form>
在表单上，定义为属性方法"POST"并添加属性"enctype"
mysql_query("UPDATE images SET source ='".mysql_real_escape_string( $output )."' WHERE id = X");
请使用MYSQL_REAL_ESCAPE_STRING
PHP函数:MYSQL_REAL_ESCAPE_STRING
你的PHP.INI CODE
file_uploads = On
upload_max_filesize = 20M