<?php
$filedir = 'uploads/';
echo "<img src='$filedir".$user->data()->username."'></img>";
?>
有谁能帮我解释一下如何用PHP回显吗
你的路径看起来像。如果
$user值为'abdulla'，则path为uploads/abdulla。这里没有提到文件扩展名(.jpg/.png)
<?php
$filedir = 'uploads/';
$user = $user->data()->username;
if (isset($user)) {
?>
<img src="<?php echo $filedir ?>/<?php echo $user ?>"/>
<?php
} else {
echo 'User is empty';
}
?>
改进代码
<?php
$filedir = 'uploads/';
$user = $user->data()->username;
if (isset($user)) {
?>
<img src="<?php echo $filedir ?>/<?php echo $user ?>.jpg"/>
<?php
} else {
echo 'User is empty';
}
?>
显示uploads/abdulla.jpg路径
尝试如下:
<?php
$filedir = 'uploads/';
?>
<img src="<?php echo $filedir.$user->data()->username?>"/>;