如何将字符串数组与 mysqli 预准备语句绑定


How can I bind an array of strings with a mysqli prepared statement?

我需要将一个值数组绑定到WHERE IN(?)子句。我该怎么做?

这有效:

$mysqli = new mysqli("localhost", "root", "root", "db");
if(!$mysqli || $mysqli->connect_errno)
{
    return;
}
$query_str = "SELECT name FROM table WHERE city IN ('Nashville','Knoxville')";
$query_prepared = $mysqli->stmt_init();
if($query_prepared && $query_prepared->prepare($query_str))
{
    $query_prepared->execute();

但是我无法使用这样的bind_param:

$query_str = "SELECT name FROM table WHERE city IN (?)";
$query_prepared = $mysqli->stmt_init();
if($query_prepared && $query_prepared->prepare($query_str))
{
    $cities = explode(",", $_GET['cities']);
    $str_get_cities = "'" . implode("', '", $get_cities) . "'"; // This equals 'Nashville','Knoxville'
    $query_prepared->bind_param("s", $cities);
    $query_prepared->execute();

我做错了什么?

我也尝试过call_user_func_array,但我似乎无法获得正确的语法。

在我的文章中,Mysqli 为 IN 子句准备了具有多个值的语句:

PHP 8.2 方式. execute_query((

从 PHP 8.2 开始,您可以使用一个方便的函数 execute_query((

// INSERT example
$sql = "INSERT INTO users (email, password) VALUES (?,?)"; // sql
$mysqli->execute_query($sql,[$email, $password]); // in one go

如果您的数组长度可变,则需要动态创建占位符列表

// WHERE IN example
$array = ['Nashville','Knoxville']; // our array
$parameters = str_repeat('?,', count($array) - 1) . '?'; // placeholders
$sql = "SELECT name FROM table WHERE city IN ($parameters)"; // sql
$result = $mysqli->execute_query($sql, $array); // in one go
$data = $result->fetch_all(MYSQLI_ASSOC); // fetch the data   

PHP 8.1 方式。数组到 execute(( 中

从 PHP 8.1 开始,您可以直接传递数组来执行:

// INSERT example
$sql = "INSERT INTO users (email, password) VALUES (?,?)"; // sql
$stmt = $mysqli->prepare($sql); // prepare
$stmt->execute([$email, $password]); // execute with data! 
// WHERE IN example
$array = ['Nashville','Knoxville']; // our array
$parameters = str_repeat('?,', count($array) - 1) . '?'; // placeholders
$sql = "SELECT name FROM table WHERE city IN ($parameters)"; // sql
$stmt = $mysqli->prepare($sql); // prepare
$stmt->execute($array);
$result = $stmt->get_result(); // get the mysqli result
$data = $result->fetch_all(MYSQLI_ASSOC); // fetch the data   

旧版本,准备/绑定/执行方式

对于早期版本,任务更加复杂。

// INSERT example
$sql = "INSERT INTO users (email, password) VALUES (?,?)"; // sql
$data = [$email, $password]; // put your data into array
$stmt = $mysqli->prepare($sql); // prepare
$stmt->bind_param(str_repeat('s', count($data)), ...$data); // bind 
$stmt->execute();

虽然,就像你的情况一样,我们有任意数量的占位符,但我们将不得不添加更多的代码。

  • 首先,我们需要创建一个字符串,其中包含与数组中元素数量一样多的?标记。为此,我们将使用str_repeat()非常方便的功能。
  • 然后,必须将这个带有逗号分隔问号的字符串添加到查询中。虽然它是一个变量,但在这种情况下它是安全的,因为它只包含常量值
  • 那么必须像任何其他查询一样准备此查询
  • 然后我们需要创建一个字符串,其中包含要与 bind_param(( 一起使用的类型。请注意,通常没有理由对绑定变量使用不同的类型 - mysql 很乐意接受它们作为字符串。有边缘情况,但极为罕见。对于日常使用,您可以始终保持简单,并使用"s"表示所有内容。 str_repeat()再次出手相救。
  • 然后我们需要将数组值绑定到语句中。不幸的是,你不能像这个$stmt->bind_param("s", $array)那样把它写成一个变量,bind_param()中只允许标量变量。幸运的是,有一个参数解包运算符可以完全满足我们的需要 - 将值数组发送到函数中,就好像它是一组不同的变量一样!
  • 其余的像往常一样 - 执行查询,获取结果并获取数据!

所以正确的示例代码是

$array = ['Nashville','Knoxville']; // our array
$in    = str_repeat('?,', count($array) - 1) . '?'; // placeholders
$sql   = "SELECT name FROM table WHERE city IN ($in)"; // sql
$stmt  = $mysqli->prepare($sql); // prepare
$types = str_repeat('s', count($array)); //types
$stmt->bind_param($types, ...$array); // bind array at once
$stmt->execute();
$result = $stmt->get_result(); // get the mysqli result
$data = $result->fetch_all(MYSQLI_ASSOC); // fetch the data   

尽管此代码相当大,但它比本主题中迄今为止提供的任何其他合理解决方案都要小得多。

不能用一个问号绑定两个变量!

对于绑定的每个变量,都需要一个问号

"bind_param"检查每个变量是否符合要求。之后,字符串值放在引号之间。

这将不起作用:

"SELECT name FROM table WHERE city IN (?)"; ( becomes too )
$q_prepared->bind_param("s", $cities);
"SELECT name FROM table WHERE city IN ('city1,city2,city3,city4')";

它必须是:

"SELECT name FROM table WHERE city IN (?,?,?,?)"; ( becomes too )
$q_prepared->bind_param("ssss", $city1, $city2, $city3, $city4);
"SELECT name FROM table WHERE city IN ('city1', 'city2', 'city3', 'city4')";

$query_prepared->bind_param逐个引用字符串参数。并且变量的数量和字符串类型的长度必须与语句中的参数匹配。

$query_str = "SELECT name FROM table WHERE city IN ('Nashville','Knoxville')";

将成为

$query_str = "SELECT name FROM table WHERE city IN (?,?)";

现在bind_param必须是

bind_param("ss", $arg1, $arg2)

有了这个

$query_str = "SELECT name FROM table WHERE city IN (?)";

bind_param

bind_param("s", $cities)

你会得到:

$query_str = "SELECT name FROM table WHERE city IN ('Nashville,Knoxville')";

这就是数组不起作用的原因。这一事实的唯一解决方案是 call_user_func_array .

如果初始化语句,则不需要执行以下操作:

$query_prepared = $mysqli->stmt_init();
if($query_prepared && $query_prepared->prepare($query_str)) {

这是正确的:

$query_prepared = $mysqli->stmt_init();
if($query_prepared->prepare($query_str)) {

如果您不想使用 call_user_func_array并且只有少量参数,则可以使用以下代码执行此操作。

[...]
$cities = explode(",", $_GET['cities']);
if (count($cities) > 3) { echo "too many arguments"; }
else
{
    $count = count($cities);
    $SetIn = "(";
    for($i = 0; $i < $count; ++$i)
    {
        $code .= 's';
        if ($i>0) {$SetIn.=",?";} else {$SetIn.="?";}
    }
    $SetIn .= ")";
    $query_str = "SELECT name FROM table WHERE city IN " . $SetIn;
    // With two arguments, $query_str will look like
    // SELECT name FROM table WHERE city IN (?,?)
    $query_prepared = $mysqli->stmt_init();
    if($query_prepared->prepare($query_str))
    {
        if ($count==1) { $query_prepared->bind_param($code, $cities[0]);}
        if ($count==2) { $query_prepared->bind_param($code, $cities[0], $cities[1]);}
        if ($count==3) { $query_prepared->bind_param($code, $cities[0], $cities[1], $cities[2]);
        // With two arguments, $query_prepared->bind_param() will look like
        // $query_prepared->bind_param("ss", $cities[0], $cities[1])
        }
        $query_prepared->execute();
    }
    [...]
}

我建议您尝试一下call_user_func_array才能到达。

寻找nick9v的解决方案.

mysqli_stmt::bind_param

这样使用call_user_func_array:

$stmt = $mysqli->prepare("INSERT INTO t_file_result VALUES(?,?,?,?)");
$id = '1111';
$type = 2;
$result = 1;
$path = '/root';
$param = array('siis', &$id, &$type, &$result, &$path);
call_user_func_array(array($stmt, 'bind_param'), $param);
$stmt->execute();
printf("%d row inserted. 'n", $stmt->effected_rows);
$stmt->close;

从 PHP 版本 8.1 开始,不再需要绑定。与 5.0 版以来的 PDO 一样,您现在可以将参数作为数组直接传递给 execute 方法。

$mysqli       = new mysqli("localhost", "root", "root", "db");
$params       = ['Nashville','Knoxville'];
$placeholders = str_repeat('?,', count($params) - 1) . '?'
$query        = "SELECT name FROM table WHERE city IN ($placeholders)";
$stmt         = $mysqli->prepare($query);
$stmt->execute($params);

另一个示例,如果您有一个关联数组,其键与列名匹配:

$mysqli       = new mysqli("localhost", "root", "root", "db");
$data         = ["bar" => 23, "baz" => "some data"];
$params       = array_values($data);
$placeholders = str_repeat('?,', count($params) - 1) . '?'
$columns      = implode("`,`", array_keys($data));
$query        = "INSERT INTO foo (`$columns`) VALUES ($placeholders)";
$stmt         = $mysqli->prepare($query);
$stmt->execute($params);

另外值得一提的是,该库现在默认在发生错误时抛出异常。在版本 8.1 之前,情况并非如此。

我也遇到了这个问题,并在发现大多数人都在使用call_user_func_array之前让它与eval一起工作:

$fields = array('model', 'title', 'price'); // Fields in WHERE clause
$values = array( // Type and value for each field
    array('s', 'ABCD-1001'),
    array('s', '[CD] Test Title'),
    array('d', '16.00')
);
$sql = "SELECT * FROM products_info WHERE "; // Start of query
foreach ($fields as $current) { // Build where clause from fields
    $sql .= '`' . $current . '` = ? AND ';
}
$sql = rtrim($sql, 'AND '); // Remove last AND
$stmt = $db->prepare($sql);
$types = ''; $vals = '';
foreach ($values as $index => $current_val) { // Build type string and parameters
    $types .= $current_val[0];
    $vals .= '$values[' . $index . '][1],';
}
$vals = rtrim($vals, ','); // Remove last comma
$sql_stmt = '$stmt->bind_param("' . $types . '",' . $vals . ');'; // Put bind_param line together
eval($sql_stmt); // Execute bind_param
$stmt->execute();
$stmt->bind_result($col1, $col2, $col3, $col4, $col5, $col6); // This could probably also be done dynamically in the same way
while ($stmt->fetch()) {
    printf("%s %s %s %s %s %s'n", $col1, $col2, $col3, $col4, $col5, $col6);
}

php 8.2 用 execute_query 解决了所有问题

$this->execute_query($query, $parms);

喜欢

$query = "SELECT * FROM users WHERE `email` IN (?) LIMIT 1";
$parms = ["xyx@gmailx.com"];
$this->execute_query($query, $parms);

还记得 ? 是占位符和 ?(占位符(与count($parms(是相同的数字,可以通过多种方式完成。

所以在你的情况下应该是

$query = "SELECT name FROM table WHERE city IN (? , ?)";
$parms = ['Nashville','Knoxville'];
$this->execute_query($query, $parms);

https://www.php.net/manual/en/mysqli.execute-query

如果要先创建动态$query,则

$query = "SELECT name FROM table WHERE city IN (".implode(",",array_map(fn()=>"?",$parms)).")";

我这样做的方式是:准备带有所有单独问号的查询,以及类型字符串。

$cities = array('Nashville', 'Knoxville');
$dibs = '';
$query = "SELECT name FROM table WHERE city IN (";
$marks = array();
foreach ($cities as $k => $city) {
    // i, s, b, d type based on the variables to bind.
    $dibs .= 's';
    array_push($marks, '?');
}
$query .= implode(',', $marks) . ')';

连接。

$mysql = new mysqli($host, $user, $pass, $dbname);
$statement =
    $mysql->prepare($query)
OR    die(sprintf(
        'Query error (%s) %s', $mysql->errno, $mysql->error
    ))
;

然后使用"..."标记/省略号(文档(以绑定数组。

if ($statement) {
    $statement->bind_param($dibs, ...$cities);
    $statement->execute();
    $statement->close();
}
$mysql->close();

我知道它有点违背了为了转义而绑定的目的(但至少它适用于整数列表,即 ID(。