使用数组精确地替换单词 - exact word replacement using arrays

我有一个值和链接的数组，并且只需要用链接替换内容中的确切值一次。对于这种情况，preg_replace可以提供如下帮助:

Array ( 
[0] => Array ( [keyword] => this week [links] => http://google.com ) 
[1] => Array ( [keyword] =>this [links] => http://yahoo.com ) 
[2] => Array ( [keyword] => week [links]=> http://this-week.com ) ) 
)

正文为:

$content = "**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.";

我尝试用字符串替换做-因为数组可以用于字符串替换，但随后所有的出现都被替换。我试图使用substr_replace，与位置，但它不工作，因为我想是。

$pos = strpos($content,$keyword);
if($pos !== false){
    substr_replace($content,$link,$pos,strlen($keyword));
}

和preg_replace，使用循环数组:

preg_replace('/'.$keyword.'/i', $link, ($content),1);

这是一种工作，它只替换一次关键字与链接，但如果关键字是复合的(this week)，它被替换为this和week，这是错误的…

非常感谢你的帮助……谢谢。

$link是问题-如果没有'http://' works fine…

如果您使用某种'ID'代替链接，在preg_replace中使用它，当这完成后，您可以调用str_replace并将ID替换为真正的链接?

$content = preg_replace('/'.$keyword.'/i', $IDS, ($content),1);
$content = str_replace($IDS, $link, $content);

我编写的示例代码替换了所有的值。我不知道你想用什么替换文本所以我输入sample text

 $content = "**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.";
 $replacement = array('[linkthiswWeek]', '[links_this]','[links_Week]');
 $patterns = array('/This week/', '/This/', '/week/');
 echo preg_replace($patterns, $replacement, $content);

输出:

**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news.**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news.**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news.

您可以根据需要修改$replacement数组

Robert的回答是有效的，但是替换了每一个不需要的出现。在preg replace的末尾添加'，1'只替换每个出现一次。

。Echo preg_replace($patterns， $replacement， $content, 1);