在.NET中，使用AttributeRouting，我们可以为每个Action Method添加Route。低于
[HttpGet, Route("Create-Project")]
public ActionResult CreateProject()
{
return View();
}
所以，在上面的代码中。。。第1行表示我们可以提到每个Action Method的路由。所以url会变成下面的样子。。
http://domainname/Create-Project
问题
它在PHP MVC CI中可行吗？现在我必须在config文件夹中的route.php中编写代码。
在routes.php中，您可以将其定义为
语法
$route['short_url_name'] = 'complete/path/for/url';
示例
$route['Contact-Us'] = 'home/contact';
$route['Blog'] = 'home/blog';
$route['Our-Work'] = 'home/work';
所以URL看起来像
http://domain.com/Contact-Us
http://domain.com/Blog
http://domain.com/Our-Work
Codeigner.com示例
在Application/config/router.php中，您可以添加一些类似的配置：
$route['Create-Project'] = 'home/welcome';
所以，每次访问http://domain.com/Create-Project，它会将您重定向到http://domain.com/home/welcome
如果你正在寻找数据库驱动的动态路由，你可以这样做，否则你可以遵循@abdulla的建议。
动态路由的表结构（表名示例：路由）。
id | slug |route
---------------------------------------------
1 |Pankaj |controller/method/id of user
2 |Abdulla |controller/method/id of user
3 |Niranjan |controller/method/id of user
控制器内
$this->load->helper('text');
$slug = $this->input->post("username");// example if you want the username in url as route.
$slug = url_title(convert_accented_characters($slug), 'dash', TRUE);
$slug = $this->Routes_model->validate_slug($slug);
$route['slug'] = $slug;
$route_id = $this->Routes_model->save($route);
$route_id将在routes表中具有路由id，在users table中插入路由id和段塞（对于哪个表，您想要动态路由）
这是路线模型的代码
<?php
class Routes_Model extends CI_Model {
var $file_name;
function __construct()
{
parent::__construct();
$this->file_name = APPPATH.'config/routes'.EXT;
}
function check_slug($slug, $id=false)
{
if($id)
{
$this->db->where('id !=', $id);
}
$this->db->where('slug', $slug);
return (bool) $this->db->count_all_results('routes');
}
function validate_slug($slug, $id=false, $count=false)
{
if(is_numeric($slug))
{
$slug = '';
$characters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
for ($i = 0; $i < 3; $i++)
{
$slug .= $characters[rand(0, strlen($characters) - 1)];
}
}
if($this->check_slug($slug.$count, $id))
{
if(!$count)
{
$count = 1;
}
else
{
$count++;
}
return $this->validate_slug($slug, $id, $count);
}
else
{
return $slug.$count;
}
}
function save($route)
{
// print_r($route);exit;
if(!empty($route['id']))
{
$this->db->where('id', $route['id']);
$this->db->update('routes', $route);
return $route['id'];
}
else
{
$this->db->insert('routes', $route);
return $this->db->insert_id();
}
}
}
?>
我检查过的一个条件是，如果用户名是一个数字，我将在validate_slug()中生成3个字符的长度。
现在按文件名MY_Router.php 在core文件夹中添加以下代码
<?php
class My_Router extends CI_Router
{
function __construct()
{
parent::__construct();
}
// this is here to add an additional layer to the routing system.
//If a route isn't found in the routes config file. then it will scan the database for a matching route.
function _parse_routes()
{
$segments = $this->uri->segments;
$segments = array_splice($segments, -2, 2);
// Turn the segment array into a URI string
$uri = implode('/', $segments);
// Is there a literal match? If so we're done
if (isset($this->routes[$uri]))
{
return $this->_set_request(explode('/', $this->routes[$uri]));
}
// Loop through the route array looking for wild-cards
foreach ($this->routes as $key => $val)
{
// Convert wild-cards to RegEx
$key = str_replace(':any', '.+', str_replace(':num', '[0-9]+', $key));
// Does the RegEx match?
if (preg_match('#^'.$key.'$#', $uri))
{
// Do we have a back-reference?
if (strpos($val, '$') !== FALSE AND strpos($key, '(') !== FALSE)
{
$val = preg_replace('#^'.$key.'$#', $val, $uri);
}
return $this->_set_request(explode('/', $val));
}
}
//look through the database for a route that matches and apply the same logic as above :-)
//load the database connection information
require_once BASEPATH.'database/DB'.EXT;
if(count($segments) == 1)
{
$row = $this->_get_db_route($segments[0]);
if(!empty($row))
{
return $this->_set_request(explode('/', $row['route']));
}
}
else
{
$segments = array_reverse($segments);
//start with the end just to make sure we're not a multi-tiered category or category/product combo before moving to the second segment
//we could stop people from naming products or categories after numbers, but that would be limiting their use.
$row = $this->_get_db_route($segments[0]);
//set a pagination flag. If this is set true in the next if statement we'll know that the first row is segment is possibly a page number
$page_flag = false;
if($row)
{
return $this->_set_request(explode('/', $row['route']));
}
else
{
//this is the second go
$row = $this->_get_db_route($segments[1]);
$page_flag = true;
}
//we have a hit, continue down the path!
if($row)
{
if(!$page_flag)
{
return $this->_set_request(explode('/', $row['route']));
}
else
{
$key = $row['slug'].'/([0-9]+)';
//pages can only be numerical. This could end in a mighty big error!!!!
if (preg_match('#^'.$key.'$#', $uri))
{
$row['route'] = preg_replace('#^'.$key.'$#', $row['route'],$uri);
return $this->_set_request(explode('/', $row['route']));
}
}
}
}
// If we got this far it means we didn't encounter a
// matching route so we'll set the site default route
$this->_set_request($this->uri->segments);
}
function _get_db_route($slug)
{
return DB()->where('slug',$slug)->get('routes')->row_array();
}
}
上述文件非常重要。当codeigniter第一次在core文件夹中运行文件时，这将创建您想要的slug。无需在routes.php文件中添加任何路由。
现在，在显示用户时，您可以在users表中shud回显slug。
假设控制器名称为users，方法名称为edit_user。
你的控制器代码会像这样，
function edit_user($id){
// fetch the data related to $id, and load the view here
}
在url中，如果它看到Niranjan，它将自动从routes表中选择路由，并进入您的函数edit_user()。
是的方法看起来很长，但效果很好，我在所有的电子商务网站上都使用它