mysql_result conversion to sqlsrv


mysql_result conversion to sqlsrv

我刚开始学习PHP,很难将mysql_result转换为使用sqlsrv的东西。

我尝试转换的代码是:(编辑后包含完整代码)

 function database($querydb) {
global $global;
global $field;
if (isset($global['queries'])) {
    $global['queries']++;
} else {
    $global['queries'] = "1";
}
$field['queries'] = $global['queries'];
if (isset($global['query_log'])) {
    $global['query_log'] .= "'n<br>$querydb";
} else {
    $global['query_log'] = "$querydb";
}
$serverName = "XXX";
$uid = "XXX";
$pwd = "XXX";
$dbName = "XXX";

$connectionInfo = array("UID" => $uid, "PWD" => $pwd, "Database" => $dbName, "ReturnDatesAsStrings"=>true);
$conn = sqlsrv_connect($serverName, $connectionInfo);
$stmt = sqlsrv_query($conn, $querydb) or return_error("Query Error: $querydb");
    while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC) ) 
        {
        $global['dbresult'] = $row;
        }

if ((substr($querydb,0,6)!="INSERT") && (substr($querydb,0,6)!="UPDATE") && (substr($querydb,0,6)!="DELETE")) {
while ($row1 = sqlsrv_fetch_array($stmt))
{
$global['dbnumber'] = mysql_numrows($global['dbresult']);  // original $dbnumber
}
return;
}
function return_error($error) {
print $error;
exit;
}
function date_status($date, $username) {
global $global;
global $field;
global $input;
global $text;
$status = "0";
if ($username!="") {
    $query = "SELECT countedrow.total, id, start_date, end_date FROM calendar JOIN (SELECT total = COUNT(*) FROM oc_calendar) AS countedrow ON 1=1";
    database($query);

    for ($i = 0; $i < $global['dbnumber']; $i++) {
        $status = "1";
        $event_id = sqlsrv_fetch_array($global['dbresult'],$i,"id"); 

    }
}
return $status;
}

我尝试过sqlsrv_get_field、sqlsrv_fetch、sqlsrv _fetch_array,但我显然没有正确理解语法,并且理解错误,因为我得到了一个错误:

sqlsrv_fetch_array()期望参数1是资源,数组在…中给定

无论我做什么。

如何从数组中提取id以设置$event_id?我哪里错了?

$querydb = "SELECT countedrow.total, id, start_date, end_date FROM oc_calendar JOIN (SELECT total = COUNT(*) FROM oc_calendar) AS countedrow ON 1=1";
$stmt = sqlsrv_query($conn, $querydb);
if( $stmt === false) {
    die( print_r( sqlsrv_errors(), true) );
}
while($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
    $event_id = $row["id"];
}

这行得通吗?

你为什么要在一段时间内将所有行单独映射到全局变量,然后再次循环全局变量!如果需要从函数返回全局,则直接循环,然后将其作为返回数组而非全局传递

你说你不知道如何为sqlsrv_fetch_array()提供有效的第一个参数,但你的代码已经做对了:

$stmt = sqlsrv_query($conn, $querydb) or return_error("Query Error: $querydb");
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC) ) {
}

但你会迷失在自己的意大利面条中:

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC) ) 
{
    $global['dbresult'] = $row;
}
$event_id = sqlsrv_fetch_array($global['dbresult'],$i,"id"); 

我真诚地建议您放弃这个代码,从头开始。