IF ELSE statement php

本文关键字：php statement ELSE IF | 更新日期: 2023-09-27

我有一个表单，在完成后存储您的fbid。我想用if-else来检查此人是否填写了表格。为此，我匹配id。然而，if-elses语句显然不起作用。

这是if else:

<?php

    $con = mysql_connect("localhost","fbappsadmin","dbP@ssw0rd");
        mysql_select_db("jetstardatabase", $con);
            if($me)
      {
      $fbid= $facebook->api('/me');
      $fbme = $fbid['id'];
      $fbName = $fbid['name'] ;  
      $fbEmail = $fbid['email'];

        $sql = "SELECT fbId FROM orders";
        $result = $mysqli->query($sql);
        while (list($fb)=$result->fetch_row()) 
        {

if ($fbme ==$fb)
    {
    ?>
        <label id ="quantity" >Quantity</label>
        <div class = "form">
            <form action="" method="post"  style="visibility:hidden" >
                    <select name="list" id="list">
                    <option value="1">1</option>
                    <option value="2">2</option>
                    </select>
                    <input type="submit" name="submit" id="submit" value="Buy!" />
            </form>
        </div>
        <?php
        }
        else
        {
        ?>
        <label id ="quantity" >Quantity</label>
        <div class = "form">
            <form action="" method="post"  >
                    <select name="list" id="list">
                    <option value="1">1</option>
                    <option value="2">2</option>
                    </select>
                    <input type="submit" name="submit" id="submit" value="Buy!" />
            </form>
        </div>
        <?php
        }
}}?>

您应该添加以下代码进行调试：

if ($fbme ==$fb)
{
    [your code]
}
else
{
    var_dump($fbme);
    var_dump($fb);
}

然后你可以看到，你的值出了什么问题，以及为什么它们与不匹配