我试图在PHP类中构建一个函数,但无论何时调用该函数,我都只返回第一个变量。
class Nums
{
private $a = 7;
private $b = 8;
public function sum()
{
return $this->a + $this->b;
}
public function __set($name,$value) {
switch($name) {
case 'a':
return $this->setA($value);
case 'b':
return $this->setB($value);
}
}
public function __get($name) {
switch($name) {
case 'a':
return $this->getA();
case 'b':
return $this->getB();
}
}
private function setA($i) {
$this->a = $i;
}
private function getA() {
return $this->$a;
}
private function setB($i) {
$this->b = $i;
}
private function getB() {
return $this->$b;
}
}
我是不是做错了什么,因为我真的看不出这个逻辑有什么错。
它对我很有效。以下是我尝试的结果,它输出了15
。
PHP代码:
<?php
class Nums
{
private $a = 7;
private $b = 8;
public function sum()
{
return $this->a + $this->b;
}
}
$obj = new Nums();
$c = $obj->sum();
echo $c;
?>
输出:
15
class Nums
{
private $a = 7;
private $b = 8;
public function sum()
{
return $this->a + $this->b;
}
}
$numObj = new Nums();
echo $numObj->sum();
运行此代码会为我返回15