选择中的两种类型的选项值 - Two types of options values in select

Two types of options values in select

本文关键字：选项类型两种选择 | 更新日期: 2023-09-27

$r=mysql_query("SELECT city.id as city_id,city.city_name,locality.id,locality.area_name  ".
               "FROM city, locality  ".
               "WHERE city.id = locality .city_id order by city_id"); 
$previous = '';
while($rss=mysql_fetch_object($r)) { ?>
    <?php if (empty($previous) || $previous != $rss->city_id) { ?>
        <legend><?=$rss->city_name?></legend>
    <?php } ?> 
    <?php $previous = $rss->city_id; ?>
    <input type="checkbox" name="sub_type[]" id="sub_type" value="<?=$rss->id?>" />
    <span><?=$rss->area_name?></span><br/>
<?php
}
?>

这是我的城市名称和区域名称记录列表在复选框中，现在我想在选择框中显示相同的东西，城市名称为红色，然后是其子区域名称，它的小示例 http://www.99acres.com/作为此站点上的城市显示

无需为您编写代码，您应该能够调整此代码以满足您的需求。

<select name="SELECTNAME">
<?php while($rss=mysql_fetch_object($r)) {
         echo '<option value="' . $value . '" ';
              if () { // Put your if statement code here for when you want the option to be coloured red.
                  echo 'YOUR RED CLASS';
              }
         echo '>' . $name . '</option>';
     }
?>
</select>

这就是你想要的吗：

$r=mysql_query("SELECT city.id as city_id,city.city_name,locality.id,locality.area_name  ".
               "FROM city, locality  ".
               "WHERE city.id = locality .city_id order by city_id"); 
$previous = '';
?>
<select name="foo">
<?php while($rss=mysql_fetch_object($r)) { ?>
    <?php if (empty($previous) || $previous != $rss->city_id) { ?>
        <option name="city[]" style="color:red" value="<?=$rss->city_name?>"><?=$rss->city_name?></option>
    <?php } ?> 
    <?php $previous = $rss->city_id; ?>
    <option name="sub_type[]" id="sub_type" value="<?=$rss->id?>"><?=$rss->area_name?></option>
<?php } ?>
</select>