REST SERVER使用CodeIgniter 3获取函数


REST SERVER get function using CodeIgniter 3

我目前正在研究rest api,我正在chris的rest服务器上使用一个ci框架,当我把id放在链接中时,我的users_get出现了问题,例如,"http://localhost/api/example/users/id/1"它仍然显示数据库中的所有数据,我的查询错了吗?在这里。

C控制器

public function users_get()
{
    // Users from a data store e.g. database
    $users = 
             $result=$this->regusers->get(); 

    $id = $this->get('result');
    // If the id parameter doesn't exist return all the users
    if ($id === NULL)
    {
        // Check if the users data store contains users (in case the database result returns NULL)
        if ($users)
        {
            // Set the response and exit
            $this->response($users, REST_Controller::HTTP_OK); // OK (200) being the HTTP response code
        }
        else
        {
            // Set the response and exit
            $this->response([
                'status' => FALSE,
                'message' => 'No users were found'
            ], REST_Controller::HTTP_NOT_FOUND); // NOT_FOUND (404) being the HTTP response code
        }
    }
    // Find and return a single record for a particular user.
    $id = (int) $id;
    // Validate the id.
    if ($id <= 0)
    {
        // Invalid id, set the response and exit.
        $this->response(NULL, REST_Controller::HTTP_BAD_REQUEST); // BAD_REQUEST (400) being the HTTP response code
    }
    // Get the user from the array, using the id as key for retreival.
    // Usually a model is to be used for this.
    $user = NULL;
    if (!empty($users))
    {
        foreach ($users as $key => $value)
        {
            if (isset($value['result']) && $value['result'] === $id)
            {
                $user = $value;
            }
        }
    }
    if (!empty($user))
    {
        $this->set_response($user, REST_Controller::HTTP_OK); // OK (200) being the HTTP response code
    }
    else
    {
        $this->set_response([
            'status' => FALSE,
            'message' => 'User could not be found'
        ], REST_Controller::HTTP_NOT_FOUND); // NOT_FOUND (404) being the HTTP response code
    }
}

型号

 <?php 

类调节器扩展CI_Model{

public function get(){
    $query=$this->db->get('tbl_user');
    return $query->result();
}

}

查看

<li><a href="<?php echo site_url('api/example/users'); ?>">Users</a> - defaulting to JSON</li>
        <li><a href="<?php echo site_url('api/example/users/format/csv'); ?>">Users</a> - get it in CSV</li>
        <li><a href="<?php echo site_url('api/example/users/id/1'); ?>">User #1</a> - defaulting to JSON  (users/id/1)</li>
        <li><a href="<?php echo site_url('api/example/users/1'); ?>">User #1</a> - defaulting to JSON  (users/1)</li>
        <li><a href="<?php echo site_url('api/example/users/id/1.xml'); ?>">User #1</a> - get it in XML (users/id/1.xml)</li>
        <li><a href="<?php echo site_url('api/example/users/id/1/format/xml'); ?>">User #1</a> - get it in XML (users/id/1/format/xml)</li>
        <li><a href="<?php echo site_url('api/example/users/id/1?format=xml'); ?>">User #1</a> - get it in XML (users/id/1?format=xml)</li>
        <li><a href="<?php echo site_url('api/example/users/1.xml'); ?>">User #1</a> - get it in XML (users/1.xml)</li>
        <li><a id="ajax" href="<?php echo site_url('api/example/users/format/json'); ?>">Users</a> - get it in JSON (AJAX request)</li>
        <li><a href="<?php echo site_url('api/example/users.html'); ?>">Users</a> - get it in HTML (users.html)</li>
        <li><a href="<?php echo site_url('api/example/users/format/html'); ?>">Users</a> - get it in HTML (users/format/html)</li>
        <li><a href="<?php echo site_url('api/example/users?format=html'); ?>">Users</a> - get it in HTML (users?format=html)</li>

控制器将始终返回所有用户,因为$id始终是FALSEnull,因为在用于分配给$id变量的get请求中没有'result'参数。我认为解决方案是将URL更改为以下格式api/example/users?id=1,然后在控制器中使用$id= $this->input->get("id");将其分配给变量。