Php检查时间字符串是否像“整小时”；上午8:00”； - Php check if time string whole hour like "8:00am"

Php check if time string whole hour like "8:00am"

我有一系列时间字符串，如"上午8:00"、"上午8:15"、"早上8:30"。我也有这些时间的时间戳作为数组的键，其中as time是值，因此数组如下所示：

注意：在本例中，时间戳是伪的

array(
144441415=>"8:00am", 
1444784744=>8:30am
...
.....
);

我想知道一小时是否是整小时，例如"上午8:00"、"上午9:00"是整小时但"上午8:45"或"上午9:30"不是整小时。我想从上面提到的数组中过滤整个小时。谢谢

您可以这样做：

$times = array(
    144441415=>"8:00am", 
    1444784744=>"8:30am",
    1444784745=>"8:45am",
    1444784746=>"9:00am",
    1444784747=>"10:00am",
);
foreach ($times as $time) {
    if (date("H:00:00", strtotime($time)) == date("H:i:00", strtotime($time))) {
        echo '<br>Whole Hour: '.$time;
    }
    else {
        echo '<br>Not Whole Hour: '. $time;
    }
}

谢谢Rudie我能从秒数中得到整个小时，谢谢你的提示，所以我做了这样的事情：

//Loop through each hour of the day by getting both key and value
foreach( $hours_of_day $timestamp=>$time_string )
{
    //If timestamp mod by number of seconds in hours is zero this means whole hour
    if( ($timestamp%3600) == 0 )
    {
        echo "Whole hour = $timestring<br />";
    }
}

对于可能遇到这个问题的人来说，实现这一点的最佳方法如下：

define("BR", "<br />");
$data = array(
    144441415=>"8:00am", 
    1444784744=>"8:30am"
);
$tmp_dto; 
$tmp_mins;
foreach($data as $hour){
    $tmp_dto = DateTime::createFromFormat("H:iA", $hour);
    $tmp_mins = $tmp_dto->format("i");
    if($tmp_mins == "00"){
        echo "ROUND".BR;
    } 
    else{
        echo "NOT ROUND".BR;
    }
}

输出

ROUND
NOT ROUND