将变量从视图传递到控制器的适当mvc模型是什么 - Whats the proper mvc model for passing variables from view to the controller?

Whats the proper mvc model for passing variables from view to the controller?

我有一个控制器，它有一个动作添加，基本上是在服务器上上传图像

函数相加（$number_of_images=1）｛

    $this->set('number_of_images', $number_of_images);
    if (!empty($this->data)) {
        $count = 1;
        foreach($this->data['Images'] as $entry){
            $file_name = "file" . $count;    
            if ($data_s = $this->Uploader->upload($file_name)) {
                $this->Image->saveAll($data_s);

            }   
            $count++;    
        }   
        $this->Session->setFlash("Your image(s) has been saved");
        $this->redirect(array('action'=>'index'));

    }   
}

我的添加视图基本上允许用户选择1个文件并上传

<?php
echo $this->Form->create('Images', array('type' => 'file', 'url' => array('controller' => 'images', 'action' => 'add')));
$count = 1;
while($count <= $number_of_images){
    // file name is file + image number
    $file_name = 'file' . $count;
    echo $this->Form->input($file_name, array('type' => 'file')); 
   // echo $this->Form->input("File " . $count, array('type' => 'file')); 
    $count++;
}
echo $this->Form->end('Upload');
echo $this->Html->link('Go Back To Main Page', '/images')
?>

我希望能够让用户有一个选项，能够选择一个以上的文件。例如，如果我转到cakehp/images/add/3，它将创建3个上传选择表单。

在add.ctp 中实现此选项的最佳方式是什么？

这里有一个简单的例子，说明了如何做到这一点。此表单不包括任何模型数据，但更改起来很容易。CCD_ 1将是具有CCD_ 2元素的阵列。

控制器：

function add() {    
    if(!empty($this->data)) {
        foreach($this->data['fileinfo'] as $f) {
            switch($f['error']) {
                case 4:
                    // nothing to do (i.e. user did not select a file)
                    break;
                case 0:
                    // handle uploaded file
                    break;
                default:
                    // report error message
            }
        }
    }
    $this->set('n', 5); // number of files that can be uploaded     
}

视图：

<?
echo $this->Form->create(false, array('enctype' => 'multipart/form-data'));
for($i = 0; $i < $n; $i++) {
    echo $this->Form->file("fileinfo.$i");
}
echo $this->Form->end('Upload');
?>