我有一个测试版网站，它包括名为Topics的节点。我忘记将唯一约束添加到name属性，现在有重复的节点。我使用了MERGE，希望它能找到唯一的名字，并添加关系，但显然不是这样。有没有办法将所有关系合并到一个节点上，然后删除重复的关系，这样我就可以在清理约束后添加它？
我发现了这一点，但我有多个具有不同关系的节点。有人知道如何修改它以适应我的情况吗？
//编辑
使用Michael的代码，我将块修改为：
MATCH (t:Topic)
WITH t.name as name, collect(t) as topics, count(*) as cnt
WHERE cnt > 1
WITH head(topics) as first, tail(topics) as rest
LIMIT 1000
UNWIND rest AS to_delete
OPTIONAL MATCH (to_delete)-[r:TOPIC_OF]->(g:Group)
FOREACH (x in case when r is null then [] else [1] |
MERGE (first)-[new_r:TOPIC_OF]->(g)
// in case you have to copy-rel-properties
SET new_r = r
DELETE r
)
OPTIONAL MATCH (to_delete)<-[r2:INTEREST_OF]-(p:Person)
FOREACH (x in case when r2 is null then [] else [1] |
MERGE (first)-[new_r2:INTEREST_OF]->(p)
// in case you have to copy-rel-properties
SET new_r2 = r2
DELETE r2
)
OPTIONAL MATCH (to_delete)<-[r3:SKILL_OF]-(p:Person)
FOREACH (x in case when r3 is null then [] else [1] |
MERGE (first)-[new_r3:SKILL_OF]->(p)
// in case you have to copy-rel-properties
SET new_r3 = r3
DELETE r3
)
OPTIONAL MATCH (to_delete)-[r4:TOPIC]->(p:Project)
FOREACH (x in case when r4 is null then [] else [1] |
MERGE (first)-[new_r4:TOPIC]->(p)
// in case you have to copy-rel-properties
SET new_r4 = r4
DELETE r4
)
OPTIONAL MATCH (to_delete)-[r5:NEEDS]->(p:Project)
FOREACH (x in case when r5 is null then [] else [1] |
MERGE (first)-[new_r5:NEEDS]->(p)
// in case you have to copy-rel-properties
SET new_r5 = r5
DELETE r5
)
DELETE to_delete
RETURN count(*);
运行时出现错误：
Invalid input '|': expected whitespace, comment, '.', node labels, '[', "=~", IN, STARTS, ENDS, CONTAINS, IS, '^', '*', '/', '%', '+', '-', '=', "<>", "!=", '<', '>', "<=", ">=", AND, XOR, OR or END (line 8, column 52 (offset: 276))
"FOREACH (x in case when r is null then [] else [1] |"
我错过了什么？
您可以稍微修改它以处理更多的rel:
MATCH (t:Topic)
WITH t.name as name, collect(t) as topics, count(*) as cnt
WHERE cnt > 1
WITH head(topics) as first, tail(topics) as rest
LIMIT 1000
UNWIND rest AS to_delete
OPTIONAL MATCH (to_delete)-[r:TOPIC_OF]->(g:Group)
FOREACH (x in case when r is null then [] else [1] |
MERGE (first)-[new_r:TOPIC_OF]->(g)
// in case you have to copy-rel-properties
SET new_r = r
DELETE r
)
OPTIONAL MATCH (to_delete)-[r2:TOPIC_OF2]->(g:Group)
FOREACH (x in case when r is null then [] else [1] |
MERGE (first)-[new_r2:TOPIC_OF2]->(g)
// in case you have to copy-rel-properties
SET new_r2 = r2
DELETE r2
)
DELETE to_delete
RETURN count(*);
我也遇到了类似的问题（我想）-请参阅此处的问题。虽然我的问题没有得到回答，但我提出的技巧和问题确实解决了我的问题。这有帮助吗？
我使用的查询与类似
// get all outgoing relationships
MATCH (a:Label1 { title : 'blah' })-[r]->(o)
RETURN r
// returns FOO and BAR
// for each relationship type, create one from (d) and copy the properties over
MATCH (a:Label1 { title : 'blah' })-[r:FOO]->(o), (d:Label1 { title : 'blah blah' })
CREATE (d)-[r2:FOO]->(o)
SET r2 = r
...etc...
// now do the same for incoming relationships
MATCH (a:Label1 { title : 'blah' })<-[r]-(o)
RETURN r
// returns FOO and BAR
// for each relationship type, create one from (d) and copy the properties over
MATCH (a:Label1 { title : 'blah' })<-[r:FOO]-(o), (d:Label1 { title : 'blah blah' })
CREATE (d)<-[r2:FOO]-(o)
SET r2 = r
...etc...
// finally delete node and relationships (if required)
MATCH (a:Label1 { title : 'blah' })-[r]-(o)
DELETE r, a
当然，只有当您能够分别识别由a和d标识的节点时，这才有帮助。