我目前正在通过地理编码在twitter中解析推文，并使用php显示它们。但目前我无法显示推特的链接。
但在XML中，它是提要->条目->
<link type="text/html" href="http://twitter.com/OFFICIALGRINZ/statuses/165838159928762368" rel="alternate" >
可以从这个标签中访问url吗？
这是我的密码。
<?php
$tabTitle = ' | Twitter';
$pageIntroductionHeading = 'Twitter';
$pageIntroductionContent = 'Twitter';
$column1Heading = 'London';
$column2Heading = 'New York';
$column3Heading = 'Paris';
require_once 'header.php';
require_once 'navigationMenu.php';
?>
<?php require_once 'getWeather.php'; ?>
<?php require_once 'getExchangeRates.php'; ?>
<?php require_once 'pageIntroduction.php'; ?>
<div id="obsah" class="content box">
<div class="in">
<div class="shadow">
<img src="./img/threeCities.jpg" alt="Three Cities Banner" title="Three Cities" class="thumb" />
</div>
<ul class="columns">
<li class="col1">
<h3><?php
if (isset($column1Heading)) {
echo $column1Heading;
}
?></h3>
<p>
<?php
$feed = simplexml_load_file ('http://search.twitter.com/search.atom?geocode=51.5069999695%2C-0.142489999533%2C10.0mi%22london%22&lang=en&rpp=5');
if ($feed){foreach ($feed->entry as $item) {
echo '<a href=''' . $item->author->uri. '''>' . $item->title . '</a>', '</br>' . $item->published, '</br>';
}
}
else echo "Cannot find Twitter feed!"
?>
</p>
</li>
<li class="col2">
</li>
</ul>
<div class="clear"></div>
</div>
<?php require_once 'footer.php'; ?>
您可以使用DomDocument Parser和DomXPath来访问您的链接。
$dom = new DomDocument();
$dom->load('yourfeed.xml');
$xpath = new DomXPath($dom);
$links = $xpath->query('/feed/entry/link'); // returns a DomNodeList with 0 or more elements
foreach ($links as $link)
{
// $link->getAttribute('href');
}
此代码未经测试。