PHP,Jquery(ajax)发布未捕获的语法错误:意外的标记<;


PHP,Jquery(ajax) post uncaught syntaxerror:unexpected token <

伙计们,我一直在获取这个未捕获的语法错误:意外的令牌<,它指向jquery库文件,我正在使用jquery(comment insert.js)向AJAX(comment insert-AJAX.php)发出请求,我试图删除AJAX脚本中php(?>)的结束标记,但我仍然收到错误。事实上,当我添加"require_once"行时,我收到了错误,很抱歉。

comment-insert-ajax.php

    <?php 
if(isset($_POST['task']) && $_POST['task'] == 'comment-insert')
{
    $userId = (int)$_POST['userId'];
    $comment = addslashes(str_replace("'n","<br>",$_POST['comment']));

    $std = new stdClass();
    $std->comment_id = 24;
    $std->userId = $userId;
    $std->comment = $comment;
    $std->userName = "Thabo Ambrose";
    $std->profile_img= "images/tbo.jpg";
    require_once $_SERVER['DOCUMENT_ROOT'] . 'defines.php';
   require_once MODELS_DIR . 'Comments.php'; 
    echo json_encode($std);

}
else
{
        header('location: /');
}

下面是使用"$.post"方法发出请求的Jquery文件。comment-insert.js

$(document).ready(function(){
   $('#comment-post-btn').click(function(){
        comment_post_btn_click();
    });

});

function comment_post_btn_click()
{
        var _comment = $('#comment-post-text').val();
        var _userId = $('#user-id').val();
        var _userName = $('#user-name').val();
        if(_comment.length > 0 && _userId != null)
        {
            //proceed with ajax call back
            $.post("ajax/comment-insert-ajax.php",
            {
                    task : "comment-insert",
                    userId : _userId,
                    comment : _comment
            }
            ).error(
                    function()
                    {
                        console.log("Error : ");
                    }
            ).success(
                    function(data)
                    {
                        comment_insert(jQuery.parseJSON(data));
                        console.log("Response text : "+ data);
                    }
            );

            console.log(_comment + " "+_userName + " id of "+_userId);  
        }
        else
        {
                //do something
                $('#comment-post-text').addClass('alert alert-danger');
                $('#comment-post-text').focus(function(){$('#comment-post-text').removeClass('alert alert-danger');});
        }   
        //remove text in the text area after posting
        $('#comment-post-text').val("");
}
function comment_insert(data)
{
    var t = '';
    t += '<li class="comment-holder" id="_'+data.comment_id+'">';
    t += '<div class="user-img">';
    t += '<img src="'+data.profile_img+'" class="user-img-pic">';
    t += '</div>';
    t += '<div class="comment-body">';
    t += '<h3 class="username-field">'+data.userName+'</h3>';
    t += '<div class="comment-text">'+data.comment+'</div>';
    t += '</div>'; 
    t += '<div class="comment-buttons-holder">';
    t += '<ul>';
    t += '<li class="delete-btn">x</li>';
    t += '</ul>';
    t += '</div>';  
    t += '</li>';
    $('.comments-holder-ul').prepend(t);
}

错误指向jQuery库的第7497行,它指向以下代码

    jQuery.parseJSON = function(data)
{
  return data;
}

尝试使用JSON.parse函数:

//proceed with ajax call back
    $.post("ajax/comment-insert-ajax.php",
        {
            task : "comment-insert",
            userId : _userId,
            comment : _comment
        }
    ).error(
        function()
        {
            console.log("Error : ");
        }
    ).success(
        function(data)
        {
            comment_insert(JSON.parse(data));
            console.log("Response text : "+ data);
        }
    );

    console.log(_comment + " "+_userName + " id of "+_userId);
}

尝试将数据放入数组中,然后对其进行编码

$array = ['comment_id' => 24,'userId' => $userId,'comment' => $comment,'userName' => "Thabo Ambrose",'profile_img'= "images/tbo.jpg"];

echo json_encode($array);

if(isset($_POST['task']) && $_POST['task'] == 'comment-insert')这行代码更改为if(isset($_POST['task']) && isset($_POST['task'])&&$_POST['task']== 'comment-insert')。然后将ajax调用更改为

    $.ajax({
                        url: "ajax/comment-insert-ajax.php",
                        data :{"task":"comment-insert","UserId":_userId,"comment":_comment},
                        type: "POST",       
                        dataType: "json",
    success:function(msg) { 
    }
});