在php中检查图像mime类型时出现意外错误


Checking image mime type in php unexpected error

我正在尝试确定图像的mime类型:

$image = $_FILES['image'];  //code shortened
function determineImage($imageResource){
    $errors = array();
    $types = array('gif' => IMAGETYPE_GIF,
                   'jpeg' => IMAGETYPE_JPEG,
                   'png' => IMAGETYPE_PNG,
                   'bmp' => IMAGETYPE_BMP);

    if ( !in_array(exif_imagetype($imageResource['tmp_name']), $types )) {
        $errors[] =  'Cannot determine mime type';
    }
    if ($imageResource['type'] !== 'image/gif'   ||
        $imageResource['type'] !== 'image/jpeg'  || 
        $imageResource['type'] !== 'image/pjpeg' ||
        $imageResource['type'] !== 'image/png'){
            $errors[] = 'Again cannot determine type';
    }
    return $errors;
}

我使用

   var_dump(determineImage($image)); 

此保持返回数组(1){[0]=>字符串(27)"再次无法确定类型"}

然而:

echo $image['type'];

仅返回:

image/png

我还打开了error_reporting(E_ALL)。有人知道问题出在哪里吗?我犯了一个愚蠢的错误吗?

代码是完全随机的(检查根本没有意义)

顺便说一下

if ($imageResource['type'] !== 'image/gif'   AND
    $imageResource['type'] !== 'image/jpeg'  AND
    $imageResource['type'] !== 'image/pjpeg' AND
    $imageResource['type'] !== 'image/jpg'  ...

AND not OR