在以下情况下,如何显示每月和每周的记录


How to display monthwise and week wise records in case of following scenario?

我在我的网站上使用PHP和MySQL。在我的数据库中有一个名为users的表。它有两个字段,即user_reg_date(bigint(12)) and user_last_login(bigint(12))。这两个字段以UNIX TIMESTAMP格式存储日期。整个表格结构如下:

user_id         varchar(32)
user_title      enum('Mr', 'Ms', 'Mrs')
user_first_name varchar(50)
user_last_name  varchar(50)
user_name   varchar(100)
user_password   varchar(50)
user_email  varchar(150)
user_dob    date    
user_hybridauth_p_name  varchar(100)
user_hybridauth_p_uid   varchar(100)
user_reg_date   bigint(12)
user_status     enum('enable', 'disable')
user_subscription   enum('lifetime', 'period')
user_update_date    bigint(12)
user_last_login     bigint(12)
user_last_activity  bigint(12)
user_created_staff_id   varchar(32)
user_updated_staff_id   varchar(32)
user_registered_type    enum('online', 'manual')

现在我想显示记录计数,即user_reg_date在本周日期内的用户计数,以及user_last_login在本周的日期内的记录计数。其他查询也需要显示上周以及当前日期后最近两周的此类记录计数。我还想每月显示相同的记录计数。有人能帮助我实现这一点吗?提前谢谢。我试着在两次约会之间找到这样的计数,在某种程度上效果很好。它给了我user_reg_date的日期计数,但没有给我上次登录的用户计数。我只是无法编写完美的查询。我为此编写的查询如下:

    SELECT date( FROM_UNIXTIME( user_reg_date ) ) 'Current Date', COUNT( user_reg_date ) 'registered_user_count', COUNT( user_last_login ) 'logged_in_count'
FROM users
WHERE user_reg_date >=1341100800
AND user_reg_date <=1374451200
AND user_last_login >=1341100800
AND user_last_login <=1374451200
GROUP BY date( FROM_UNIXTIME( user_reg_date ) ) , date( FROM_UNIXTIME( user_last_login ) ) 

您可以执行类似的操作

SELECT
  (SELECT COUNT(*) 
     FROM users
    WHERE user_last_login BETWEEN UNIX_TIMESTAMP(ADDDATE(CURDATE(), INTERVAL 1-DAYOFWEEK(CURDATE()) DAY))
                              AND UNIX_TIMESTAMP(ADDDATE(CURDATE(), INTERVAL 7-DAYOFWEEK(CURDATE()) DAY))
  ) logged_in_count,
  (SELECT COUNT(*) 
     FROM users
    WHERE user_reg_date   BETWEEN UNIX_TIMESTAMP(ADDDATE(CURDATE(), INTERVAL 1-DAYOFWEEK(CURDATE()) DAY))
                              AND UNIX_TIMESTAMP(ADDDATE(CURDATE(), INTERVAL 7-DAYOFWEEK(CURDATE()) DAY))
  ) registered_user_count

这是SQLFiddle演示

SELECT columnName
  SUM(CASE WHEN REQUESTMONTH=1 THEN (REQUESTTOTAL) END) Jan,
  SUM(CASE WHEN REQUESTMONTH=2 THEN (REQUESTTOTAL) END) Feb,
  SUM(CASE WHEN REQUESTMONTH=3 THEN (REQUESTTOTAL) END) Mar,
  SUM(CASE WHEN REQUESTMONTH=4 THEN (REQUESTTOTAL) END) Apr,
  SUM(CASE WHEN REQUESTMONTH=5 THEN (REQUESTTOTAL) END) May,
  SUM(CASE WHEN REQUESTMONTH=6 THEN (REQUESTTOTAL) END) Jun,
  SUM(CASE WHEN REQUESTMONTH=7 THEN (REQUESTTOTAL) END) July,
  SUM(CASE WHEN REQUESTMONTH=8 THEN (REQUESTTOTAL) END) Aug,
  SUM(CASE WHEN REQUESTMONTH=9 THEN (REQUESTTOTAL) END) Sep,
  SUM(CASE WHEN REQUESTMONTH=10 THEN (REQUESTTOTAL) END) 'Oct',
  SUM(CASE WHEN REQUESTMONTH=11 THEN (REQUESTTOTAL) END) Nov,
  SUM(CASE WHEN REQUESTMONTH=12 THEN (REQUESTTOTAL) END) 'Dec'
FROM tableName