我想找到一个正则表达式,它可以(在给定的HTML中)找到以下图像:
- 捕获于:
src=""
- 捕获于:
src=''
- 捕获于:
background=""
- 捕获于:
background=''
- 捕获于:
url("")
- 捕获于:
url('')
- 捕获于:
url()
到目前为止,我想出了:
preg_match_all("/src=(('"|'|)?(.*'.(png|gif|jpg))('"|'|))/Ui", $strHTML, $arrMatches);
preg_match_all("/background=(('"|'|)?(.*'.(png|gif|jpg))('"|'|))/Ui", $strHTML, $arrMatches);
preg_match_all("/url'(('"|'|)?((.*'.(png|gif|jpg))('"|'|))')/Ui", $strHTML, $arrMatches);
但是这些是不完整的,因为它们不包括前缀(src/background/url)。此外,在安全方面,我认为它们可以进一步改进,以防止有人进入src="http://somesite.com/someurl.exe?ext=jpg"
我们感谢在正确方向上提供的任何帮助。
编辑:
我想我明白了,尽管代码肯定可以改进,甚至可能组合和/或优化:)
/* match CSS url() links */
preg_match_all("/(url'(('"|'|)(.*'.(png|gif|jpg|jpeg))('"|'|)'))/Ui", $strHTML, $arrMatches);
Array
(
[0] => Array
(
[0] => url('test1.gif')
[1] => url(test2.gif)
[2] => url("test3.gif")
)
[1] => Array
(
[0] => url('test1.gif')
[1] => url(test2.gif)
[2] => url("test3.gif")
)
[2] => Array
(
[0] => '
[1] =>
[2] => "
)
[3] => Array
(
[0] => test1.gif
[1] => test2.gif
[2] => test3.gif
)
[4] => Array
(
[0] => gif
[1] => gif
[2] => gif
)
[5] => Array
(
[0] => '
[1] =>
[2] => "
)
)
/* match img links */
preg_match_all("/(src=('"''??)(.*'.(png|gif|jpg|jpeg))('"''??))/Ui", $strHTML, $arrMatches);
/* match background links */
preg_match_all("/(background=('"''??)(.*'.(png|gif|jpg|jpeg))('"''??))/Ui", $strHTML, $arrMatches);
如果您确定这些属性名称(src、url和background)。。。
$arr = array(
'url("http://somesite.com/someurl.exe?src=jpg")',
'url(http://somesite.com/someurl.exe?src=jpg)',
'src="http://somesite.com/someurl.exe?src=jpg"',
'src="http://somesite.com/someurl.exe?ext=jpg"',
'background="http://somesite.com/someurl.exe?src=jpg"'
);
foreach ($arr as $str) {
preg_match_all('/(?<=src=|background=|url'()(''|")?(?<image>.*?)(?='1|'))/i',$str,$matches);
echo $str;
foreach($matches['image'] as $img) {
echo "'nimage: <b>$img</b>'n";
}
echo "'n";
}