使用PHP通过url上传1000张图片


Uploading 1000 images via url using PHP

我想通过URL一键上传1000张图片。我在MYSQL数据库中存储了1000个图像URL。

所以请任何人给我PHP代码,通过mysql数据库通过URL上传那1000张图片。

目前我正在使用以下代码:-它通过发布图片的URL,每次点击上传一张图片。。。

但我想通过从数据库获取URL,一键上传1000张图片

$result = mysql_query("SELECT * FROM thumb") or die(mysql_error());
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
echo "<div>";
$oid = $row['tid'];
$th= $row['q'];
echo "</div>";
$thi = $th;
$get_url = $post["url"];
$url = trim('$get_url');
if($url){
    $file = fopen($url,"rb");
    $directory = "thumbnail/";
    $valid_exts = array("php","jpeg","gif","png","doc","docx","jpg","html","asp","xml","JPEG","bmp"); 
    $ext = end(explode(".",strtolower(basename($url))));
    if(in_array($ext,$valid_exts)){
        $filename = "$oid.$ext";
        $newfile = fopen($directory . $filename, "wb");
        if($newfile){
            while(!feof($file)){
                fwrite($newfile,fread($file,1024 * 8),1024 * 8);
            }
            echo 'File uploaded successfully';
            echo '**$$**'.$filename;
        }
        else{
            echo 'File does not exists';
        }
    }
    else{
        echo 'Invalid URL';
    }
}
else{
    echo 'Please enter the URL';
}
}

非常感谢…

您的代码已经过时,而且比需要的复杂得多。这不是一个你因为提问而获得代码的网站,这是一个学习环境。

我会给你一个例子,你可以继续:

// Select the images (those we haven't done yet):
$sItems = mysql_query("SELECT id,url FROM thumb WHERE imported=0") or die(mysql_error());
// Loop through them:
while( $fItems = mysql_fetch_assoc($sItems) ){
    $imgSource = file_get_contents($fItems['url']); // get the image
    // Check if it didn't go wrong:
    if( $imgSource!==false ){
        // Which directory to put the file in:
        $newLocation = $_SERVER['DOCUMENT_ROOT']."/Location/to/dir/"; 
        // The name of the file:
        $newFilename = basename($fItems['url'], $imgSource); 
        // Save on your server:
        file_put_content($newLocation.$newFilename);
    }
    // Update the row in the DB. If something goes wrong, you don't have to do all of them again:
    mysql_query("UPDATE thumb SET imported=1 WHERE id=".$fItems['id']." LIMIT 1") or die(mysql_error());
}

相关功能:
file_get_contents()-获取图像的内容
file_put_contents()-将此函数中给定的内容放在指定的文件中
basename()-给定一个url,它只提供文件名

重要信息:

  • 您正在使用mysql_query。这是不推荐使用的(不应再使用),请使用PDO或mysqli
  • 我建议您从命令行执行此操作,并在更新后添加一个echo,以便监视进度