我正试图从用户那里获得输入,并根据用户的输入显示文本。例如,用户输入1,浏览器应显示"一",如果用户输入2,则浏览器应显示两个。我已经为此创建了一个代码,但请任何人指导我如何更好地优化代码并使用ajax。如果有人能让我知道我该如何将其创建为wordpress plign,我将不胜感激。非常感谢。
代码如下
<!DOCTYPE html>
<html>
<head>
<title>Display quote of the day</title>
</head>
<body>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST">
Please Enter a number between 1 to 70:<br /><br />
<input type="text" name="quote-number">
<input type="submit" value="Show Quote">
</form>
<?php
//Default values
$one = "Quote one";
$two = "Quote two";
$three = "Quote three";
$four = "Quote four";
$five = "Quote five";
//Saving the value in a variable
$number = isset($_POST['quote-number']);
if ($number) {
$quotevalue = $_POST['quote-number'];
}
if ($quotevalue==1) {
echo "$one";
} elseif ($quotevalue==2) {
echo "$two";
} elseif ($quotevalue==3) {
echo "$three";
} elseif ($quotevalue==4) {
echo "$four";
} elseif ($quotevalue==5) {
echo "$five";
} else {
echo "<br /> Please enter a number from 1 to 70.";
}
?>
</body>
</html>
请使用切换语句
switch (n) {
case label1:
code to be executed if n=label1;
break;
case label2:
code to be executed if n=label2;
break;
case label3:
code to be executed if n=label3;
break;
...
default:
code to be executed if n is different from all labels;
}
更多查看此处http://www.w3schools.com/php/php_switch.asp