+-----+-------+--------+
ID | Owner | Number |
+-----+-------+--------+
com1 | peter | 103045 |
+-----+-------+--------+
com2 | deter | 103864 |
+-----+-------+--------+
嘿,伙计们。我正在处理项目的这一部分,其中用户应该输入某个ID。当他输入这个特定的ID时,应该打印出该ID行中的所有内容。在这种情况下,如果他输入 com1,它将显示:
+-----+-------+--------+
ID | Owner | Number |
+-----+-------+--------+
com1 | peter | 103045 |
+-----+-------+--------+
我使用了这个表单和代码:
形式.php
<form action="query.php" method="POST">
Enter your ID: <input type="varchar" name="id" /><br />
<input type="submit" value="Audit" />
</form>
查询.php
$con = mysql_connect("localhost", "root", "");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("livemigrationauditingdb", $con);
$input = (int) $_POST['id'];
$query = mysql_query("SELECT * FROM system_audit WHERE ID = $input");
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Owner</th>
<th>Number</th>
</tr>";
while($row = mysql_fetch_array($query))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Owner'] . "</td>";
echo "<td>" . $row['Number'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
认为你们知道错误吗? 哦,我可以不将其链接到其他页面吗? 我需要表单和代码在一个页面中。 目前我的表单链接到查询.php。 有没有办法取消这一行,它仍然有效。 谢谢!
尝试从 $input = (int( $_POST['id']中删除 (int(;
尝试删除
while($row = mysql_fetch_array($query))
并将其替换为
while($row = mysql_fetch_row($result))
同时删除 (int(,看看是否有帮助。
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Owner'] . "</td>";
echo "<td>" . $row['Number'] . "</td>";
可以替换为
echo "<td>" . $row[0] . "</td>";
echo "<td>" . $row[1] . "</td>";
echo "<td>" . $row[2] . "</td>";
您也可以将它们放在同一个页面上,如图所示
<?php
$con = mysql_connect("localhost", "root", "");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("livemigrationauditingdb", $con);
$input = (int) $_POST['id'];
if($input)
{
$query = mysql_query("SELECT * FROM system_audit WHERE ID = $input");
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Owner</th>
<th>Number</th>
</tr>";
while($row = mysql_fetch_row($query))
{
echo "<tr>";
echo "<td>" . $row[0] . "</td>";
echo "<td>" . $row[1] . "</td>";
echo "<td>" . $row[2] . "</td>";
echo "</tr>";
}
echo "</table>";
}
mysql_close($con);
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
Enter your ID: <input type="varchar" name="id" /><br />
<input type="submit" value="Audit" />
</form>
?>