PHP Regex:测试是否匹配，然后删除 - PHP Regex: Test if matches, and then remove

PHP Regex: Test if matches, and then remove

我想检查某个HTML中是否存在字符串，然后做一些事情，如果存在，将其从HTML中删除。字符串的格式为"Approved NN.NN.NN"。编写此代码的最佳方式是什么？

$html = '<div>This is some text.  Approved 11.22.12</div>';
$pattern = '/Approved [0-9][0-9]'.[0-9][0-9]'.[0-9][0-9]/';
if (preg_match($pattern, $html)){
   stuff();
   $html = preg_replace($pattern, '', $html);
}

$pattern = '/Approved's?'d{2}'.'d{2}'.'d{2}/';

我刚刚运行了以下代码：

$html = '<div>This is some text.  Approved 11.22.12</div>';
$pattern = '/Approved's?'d{2}'.'d{2}'.'d{2}/';
if (preg_match($pattern, $html)){
    $html = preg_replace($pattern, '', $html);
}
echo $html;

输出：

<div>This is some text.  </div>