这里我需要一些关于合并两个数组的帮助。
这是我有的样本代码
$tasks = array();
$task_user = new Task_User;
$task_user->setUserId($this->session_data['userId']);
$user_taskIds = $this->getUserTasks($task_user);
foreach ($user_taskIds as $row) {
$task = new Task;
// $task->setBranchId($branch_id);
$task->setTaskId($row->getTaskId());
$tasks[] = $this->getTask($task);
}
echo "<pre>";
print_r($tasks);
$pageData['userTasks'] = $tasks;
$task = new Task;
// $task->setBranchId($branch_id);
$task->setCreated($this->session_data['userId']);
$tasks1 = $this->getBranchTasks($task);
if (!empty($tasks1[0]))
{
$pageData['userTasks'] = $tasks1;
}
print_r($tasks1);
print_r($pageData['userTasks']);
$this->load->view('home',$pageData);
输出:
Array
(
[0] => Task Object
(
[task_id:Task:private] => 22
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 121
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000022
)
[1] => Task Object
(
[task_id:Task:private] => 24
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 1046
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000024
)
)
Array
(
[0] => Task Object
(
[task_id:Task:private] => 9
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 599
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000009
)
[1] => Task Object
(
[task_id:Task:private] => 10
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 313
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000010
)
)
Array
(
[0] => Task Object
(
[task_id:Task:private] => 9
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 599
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000009
)
[1] => Task Object
(
[task_id:Task:private] => 10
[service_id:Task:private] => 1
[branch_id:Task:private] => 1
[customer_id:Task:private] => 313
[lead_id:Task:private] => 0
[name:Task:private] => YTY0000010
)
)
所以,最后我需要两个对象数组应该与唯一的对象组合,并将其传递给一个数组。我试了6个小时。但是我拿不到。请帮帮我提前感谢。
在一些简短的测试中,In_array似乎能处理对象。然而,如果不揭开它们的面纱,它就无法观察到私人变量,这是我留给你的一个练习。
$tasks2 = [];
foreach($tasks as $t){
if(!in_array($t,$tasks2){
array_push($tasks2,$t);
}
}
替换此行…
if (!empty($tasks1[0]))
{
$pageData['userTasks'] = $tasks1;
}
...
进入…
if (!empty($tasks1[0]))
{
$pageData['userTasks'] = array_replace($pageData['userTasks'], $tasks1);
}
...