我想在整个网站中隐藏.php扩展，我有这个片段，它运行良好。然而，我有一个URL，我想成为规则的例外，那就是我希望它有完整的.php和所有的$_GET参数。
如何将该异常包含在此代码段中？为什么它有效？
Options +FollowSymLinks -MultiViews
# Turn mod_rewrite on
RewriteEngine On
RewriteBase /
## hide .php extension
# To externally redirect /dir/foo.php to /dir/foo
RewriteCond %{THE_REQUEST} ^[A-Z]{3,}'s([^.]+)'.php [NC]
RewriteRule ^ %1 [R=302,L]
# To internally forward /dir/foo to /dir/foo.php
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME}.php -f
RewriteRule ^(.*?)/?$ $1.php [L]
您可以添加这样的异常：
Options +FollowSymLinks -MultiViews
# Turn mod_rewrite on
RewriteEngine On
RewriteBase /
## hide .php extension
# To externally redirect /dir/foo.php to /dir/foo
RewriteCond %{THE_REQUEST} ^[A-Z]{3,}'s([^.]+)'.php [NC]
RewriteRule !^(exception1|exception2) %1/ [R=302,L]
# To internally forward /dir/foo to /dir/foo.php
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME}.php -f
RewriteRule ^(.*?)/?$ $1.php [L]
顺便说一句，这段代码和注释看起来像我过去写的：）