我想输出一条消息，只要url包含任何以p2开头的参数，例如在以下所有实例中：
example.com/?p2=hello
example.com/?p2foo=hello
example.com/?p2
example.com/?p2=
我试过：
if (!empty($GET['p2'])) {
echo "a parameter that starts with p2 , is showing in your url address";
} else {
echo "not showing";
}
这应该涵盖的所有情况
$filtered = array_filter(array_keys($_GET), function($k) {
return strpos($k, 'p2') === 0;
});
if ( !empty($filtered) ) {
echo 'a paramater that starts with p2 , is showing in your url address';
}
else {
echo 'not showing';
}
只需在$_GET数组上迭代，并在匹配时为密钥添加一个以p2开头的条件即可执行所需操作。
foreach($_GET as $key=>$value){
if (substr($key, 0, 2) === "p2"){
// do your thing
print $value;
}
}
substr($key,0,2)从字符串中提取前两个字符
尝试
if (isset($GET['p2'])) {
echo "a paramater that starts with p2 , is showing in your url address";
} else {
echo "not showing";
}
最快的方法是
if(preg_match("/(^|'|)p2/",implode("|",array_keys($_GET)))){
//do stuff
}