我正在尝试一个过滤器,看看一个文件是否存在,以及有多少:我正在尝试使用以下脚本:
$list = glob($filepath.$filenamePartial'*'.$ext);
var_dump($list);
已解决1:
$list = glob($filepath.$FsisName.'_'.$count.'_'.'*'.$ext);
if (count($list) <= 0){
$FFileUPL = $filepath.$FsisName.'_'.$count.'_'.$FileDate.'.'.$ext;
$event = move_uploaded_file($flTName, $FFileUPL);
}else{
echo 'this file Exist: '.$FsisName.'-'.$count.'-'.$FileDate.'.'.$ext.'<br>';
$event = false;
}
如何在iteratos中检索名称文件已解决2:
foreach($list as $fnames){
$eFile['smg'] .= basename($fnames).'<br>';
}
已解决:
$list = glob($filepath.$FsisName.'_'.$count.'_'.'*'.$ext);
if (count($list) <= 0){
$FFileUPL = $filepath.$FsisName.'_'.$count.'_'.$FileDate.'.'.$ext;
$event = move_uploaded_file($flTName, $FFileUPL);
}else{
echo 'this file Exist: '.$FsisName.'-'.$count.'-'.$FileDate.'.'.$ext.'<br>';
$event = false;
}
foreach($list as $fnames){
$eFile['smg'] .= basename($fnames).'<br>';
}