php:在邮件中获取资源id #6


php : getting Resource id #6 in email

我已经测试了这段代码,使用本地服务器的工具发送电子邮件,它工作正常,但在"from"部分我没有得到发件人的电子邮件,因为它应该打印在那里作为结果$email,而是我得到了这个输出"from: Resource id #6 ",到底是什么问题,因为查询似乎很好,工作?

这部分代码

$Load=$_SESSION['login_user'];
$smail= "Select email from teacher where TID = $Load ";
$errors = '';
  $email= mysql_query($smail);  
if( 
   empty($_POST['email']) || 
   empty($_POST['message']))
{
    $errors .= "'n Error: all fields are required";
}

$email_address = $_POST['email']; 
$message = $_POST['message']; 
if (!preg_match("/^[_a-z0-9-]+('.[_a-z0-9-]+)*@[a-z0-9-]+('.[a-z0-9-]+)*('.[a-z]{2,3})$/i", $email_address))
{
    $errors .= "'n Error: Invalid email address";
}
if( empty($errors))
{
    $to = $email_address; 
    $email_subject = "New mail from admin";
    $email_body = "You have received a new message. ".
    " Here are the details:'n From: $email 'n Message 'n $message"; 
    $headers = "From: $email'n"; 
    $headers .= "Reply-To: $email_address";
    $sent = mail($to,$email_subject,$email_body,$headers);      
}

执行查询后没有获取记录,请尝试以下操作

$result = mysql_fetch_assoc(mysql_query($smail));  
$email = $result['email']

使用mysql_fetch_assoc

 $result = mysql_fetch_assoc(mysql_query($email));  
 $email = $result['email']

你必须先获取你的结果。

$result= mysql_query($email);  
$row=mysql_fetch_object($result);
$email=$row->email;