我有三个表,我想从中提取数据。一个是类表,它存储所提供的类的列表,包括id、时间戳、培训师id、开始时间、上午/下午和上课天数。培训师id是一个外键,它将其绑定到一个培训师表,我在其中根据培训师的唯一id提取培训师名称。
这很好,但是我还需要显示每节课的平均出勤率。这涉及到一个具有类id外键的统计表,该表将类id与该会话的参与者数量一起放入一行中。我想返回每个类的每个课程的平均参与者数。
下面是我的select语句:SELECT
class_id AS id,
class_name,
class_trainerid,
class_starttime AS start,
class_ampm AS ampm,
class_days AS days,
trainer_id AS trainid,
trainer_name,
stat_class AS sclass,
AVG(stat_students) as stat_students_avg
FROM
$class_table
LEFT JOIN $trainer_table ON (class_trainerid = trainer_id)
LEFT JOIN stats ON (id = stat_students_avg)
GROUP BY
id
上面的代码可能表明我实际上并不知道如何做到这一点。我看过关于通过连接平均的帖子,或者在选择语句中使用选择语句,但我似乎无法将这些转换为我的问题。
编辑:下面是类表模式:
`class_id` tinyint(8) NOT NULL AUTO_INCREMENT,
`class_datereated` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`class_name` varchar(256) NOT NULL,
`class_trainerid` tinyint(8) NOT NULL,
`class_starttime` time NOT NULL,
`class_ampm` text NOT NULL,
`class_days` text NOT NULL,
PRIMARY KEY (`class_id`)
下面是训练器模式
`trainer_id` tinyint(8) NOT NULL AUTO_INCREMENT,
'trainer_datecreated` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`trainer_name` varchar(256) NOT NULL,
`trainer_password` varchar(25) NOT NULL,
`trainer_email` varchar(256) NOT NULL,
`trainer_active` tinyint(1) NOT NULL DEFAULT '1',
PRIMARY KEY (`trainer_id`),
UNIQUE KEY `email` (`trainer_email`)
,下面是stats表模式:
`stat_id` int(8) NOT NULL AUTO_INCREMENT,
`stat_datecreated` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`stat_class` int(8) NOT NULL,
`stat_students` int(8) NOT NULL,
`stat_trainer` tinyint(8) NOT NULL,
`stat_class_date` date NOT NULL,
PRIMARY KEY (`stat_id`)
输出将是php while语句的一部分,结果如下:
echo "<table class='list'>";
echo "<tr>";
echo "<th>Class Name</th><th>Trainer</th><th>Ave</th><th>Edit</th><th>Delete</th>";
echo "</tr>";
while($row = mysql_fetch_assoc($class_result))
{
echo "<tr id='class_".$row["id"]."'>";
echo "<td>".$row["class_name"]."</td>";
echo "<td class='trainer-name'>".$row["trainer_name"]."</td>";
echo "<td class='trainer-name'>".$row["stat_students_avg"]."</td>";
echo "<td class='icon'><a href='javascript:void(0);' id='class_edit_".$row["id"]."'><span class='glyphicon glyphicon-edit'></span></a></td>";
echo "<td class='icon'><a href='javascript:void(0);' id='class_delete_".$row["id"]."'><span class='glyphicon glyphicon-remove'></span></a></td>";
echo "</tr>";
}
echo "</table>";
您的ON (id = stat_students_avg)
不对应相同的值。
统计表和类表连接的唯一方式是:类表的class_trainerid和统计表的trainer_id
你可以试试这样
SELECT
class_id ,
class_name,
class_trainerid,
class_starttime as start,
class_ampm as ampm,
class_days as days,
trainer_id as trainid,
trainer_name,
stat_class as sclass,
AVG(stat_students) as stat_students_avg
FROM
$class_table
LEFT JOIN $trainer_table ON (class_trainerid = trainer_id)
LEFT JOIN stats ON (trainer_id = class_trainerid)
GROUP BY
class_id