这里:使用PHP转换子数组元素中的数组值我问了同样的问题,但数组更平坦。我试图修改代码,但不幸的是没有成功。
我怎么能合并以下数组,这样第二个数组就不会添加在第一个数组的末尾,但第一个数组中的每个子数组都会接收第二个的子数组的相应值。换句话说,我想合并子数组。这里是我的例子:
阵列01:
Array01 (
[0] => Array
(
[0] => 40292633
[1] => 412
)
[1] => Array
(
[0] => 41785603
[1] => 382
)
[2] => Array
(
[0] => 48792980
[1] => 373
)
[3] => Array
(
[0] => 44741143
[1] => 329
))
阵列02:
Array02(
[0] => Array
(
[0] => 3460581
[1] => 1407424B1
[2] => 951753
)
[1] => Array
(
[0] => 3484251
[1] => 1028325B1
[2] => 159357
)
[2] => Array
(
[0] => 3519102
[1] => 0586365A1
[2] => 456654
)
[3] => Array
(
[0] => 3529714
[1] => 1059876A1
[2] => 852258
))
最终阵列:
finalArray(
[0] => Array
(
[0] => 40292633
[1] => 412
[2] => 3460581
[3] => 1407424B1
[4] => 951753
)
[1] => Array
(
[0] => 41785603
[1] => 382
[2] => 3484251
[3] => 1028325B1
[4] => 159357
)
[2] => Array
(
[0] => 48792980
[1] => 373
[2] => 3519102
[3] => 0586365A1
[4] => 456654
)
[3] => Array
(
[0] => 44741143
[1] => 329
[2] => 3529714
[3] => 1059876A1
[4] => 852258
))
非常感谢!
尝试此代码
function merge_arrays($a1, $a2) {
return array($a1, $a2);
}
$result = array_map("merge_arrays", $a1, $a2);
foreach($result as $nr)
{
$nres[] = array_merge ($nr[0], $nr[1]);
}
试试这个:
$result = array();
$keys = array_unique( array_merge(array_keys($arr1), array_keys($arr2)) );
foreach($keys as $key) {
if( !array_key_exists($key, $arr1) ) {
$result[$key] = $arr2;
} else if( !array_key_exists($key, $arr2) ) {
$result[$key] = $arr1;
} else {
$result[$key] = array_merge($arr1[$key], $arr2[$key]);
}
}
它并不假设两个数组都具有相同的键。
如果您想使用array_map
,这是一个等效的解决方案:
$keys = array_unique( array_merge(array_keys($arr1), array_keys($arr2)) );
$result = array_map(function($key) use ($arr1,$arr2) {
if( !array_key_exists($key, $arr1) ) {
return $arr2;
} else if( !array_key_exists($key, $arr2) ) {
return $arr1;
}
return array_merge($arr1[$key], $arr2[$key]);
},
$keys);
如果你确定两个数组都有相同的密钥,你可以试试这个:
$result = array();
foreach($arr1 as $key => $arr1val) {
$result[$key] = array_merge($arr1val, $arr2[$key]);
}