我想知道是否有可能使用PHP来找出具体的日期。
例如:// Next week
$date->setDate(2014, 4, 3);
if($date->format('Y-m-d') == NEXT_WEEK){
// Do something
}elseif($date->format('Y-m-d') == NEXT_MONTH){
// DO something else
}elseif($date->format('Y-m-d') == NEXT_YEAR){
// Do something else
}
我知道我的代码不会工作，但我正在寻找的东西，将实现类似的东西吗?
Easy Going with strtotime():
<?
$date = new DateTime();
$date->setDate(2014, 5, 2);
if($date->format('U') >= strtotime("next year")){
echo "next year";
}elseif($date->format('U') >= strtotime("next month")){
echo "next month";
}elseif($date->format('U') >= strtotime("next week")){
echo "next week";
}
?>
请记住，使用>=需要您首先检查年，然后是月，然后是周，因为strtotime("next year") > strtotime("next month") > strtotime("next week")。
这可以通过DateTime对象实现，使用diff来查看两者之间的时间，像这样的东西应该可以做到:
// The date we want to check
$checkDate = new DateTime('2014-04-03', new DateTimeZone('UTC'));
// We need to compare it against today + a specific interval,
// so create a seperate DateTime object for today
$today = new DateTime('now', new DateTimeZone('UTC'));
// Check the difference between the dates
$diff = $today->diff($checkDate);
if ($diff->y == 0 && $diff->m == 0 && $diff->d == 7) {
// Date lies a week in the future
} elseif ($diff->y == 0 && $diff->m == 1 && $diff->d == 0) {
// Date lies a month in the future
} elseif ($diff->y == 1 && $diff->m == 0 && $diff->d == 0) {
// Date lies a year in the future
}
根据"下周"、"下个月"answers"明年"的各种定义，有几种方法可以使用PHP日期格式参数来实现这一点，在这里的PHP手册中有解释。还需要检查上边界，以确保日期不会超过下周/月/年。
<?php
$checkdate = strtotime('+8 days');
$datenow = time();
$diff = $checkdate - $datenow;
echo "Today: ".date("Y-m-d", $datenow)."<br/>";
echo "Target: ".date("Y-m-d", $checkdate)."<br/>";
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$years = floor($diff / (365*60*60*24));
$daytoday = date ('N', $datenow);
$dayofmonthtoday = date ('j', $datenow);
$dayofmonthtarget = date ('j', $checkdate);
$monthtoday = date ('n', $datenow);
$monthtarget = date ('n', $checkdate);
$yeartoday = date ('Y', $datenow);
$yeartarget = date ('Y', $checkdate);
// $dayofyeartoday = date('z', $datenow);
// $dayofyeartarget = date('z', $checkdate);
if ($days >= 8-$daytoday && $days <= 14-$daytoday) {
echo "Next week (Monday onwards)<br/>";
}
if ($days >= 7-$daytoday && $days <= 13-$daytoday) {
echo "Next week (Sunday onwards)<br/>";
}
if ($days >= 7 && $days <= 13) {
echo "Next week (7-13 days)<br/>";
}
if ($monthtarget == $monthtoday + 1) {
echo "Next month (Change in month)<br/>";
}
if ($monthtarget == $monthtoday + 1 && $dayofmonthtarget >= $dayofmonthtoday) {
echo "Next month (Change in month but at least same day in the month and before end of that month)<br/>";
}
if ($yeartarget == $yeartoday + 1) {
echo "Next year (Change in year)<br/>";
}
if ($yeartarget == $yeartoday + 1 && $years == 1) {
echo "Next year (Change in year but at least same day and month in the year and before end of that year)<br/>";
}
?>