这是我的第三天，我放弃了搜索和尝试。我想我已经需要这个团队的帮助了。无论如何，这段代码将打印所有不是我朋友的个人资料。我想放一个id，这样当我点击添加朋友时，它会给我一个该用户的id，我可以操作它。谢谢大家：）
<?php
require "php/dbc.php";
$temp = mysql_query("SELECT * FROM friends WHERE username = '$username'");
$friends = mysql_fetch_array($temp);
$query = mysql_query("SELECT * FROM user");
while($row = mysql_fetch_array($query)){
if($row['username'] != $username && in_array($row['username'],$friends)===false){
echo '<div class="container">';
echo '<div class="row">';
echo '<div class="col-xs-12 col-sm-6 col-md-6">';
echo '<div class="well well-sm">';
echo '<div class="row">';
echo '<div class="col-sm-6 col-md-4">';
echo '<img src="profile/'.$row['profpicxtn'].'" alt="" " />';
echo '</div>';
echo '<div class="col-sm-6 col-md-8">';
echo '<h4>';
echo ucfirst($row['fname'])." ".ucfirst($row['lname']).'</h4>';
echo '<p>';
echo '<i class="glyphicon glyphicon-envelope"></i>'.$row['email'];
echo '<br />';
echo ' <i class="glyphicon glyphicon-gift"></i>bday</p>';
echo '<input type="submit" name="name" method="post" c>+1 Add Friend</button>';
echo '</div>';
echo '</div>';
echo '</div>';
echo '</div>';
echo '</div>';
echo '</div>';
?>
在表单标记中插入添加好友按钮，为了设置要与该表单一起发送的id，您可以使用隐藏输入并在隐藏输入中设置id的值例如，如果你的id值等于$row['id']，你可以这样做
<form method="post" action="">
<input type="hidden" value=<?php echo $row['id'] ; ?> />
<input type="submit" name="submit" value="+1 Add Friend"/>
</form>
请记住，您可以使用?><?php在php脚本中跳转和跳出，这会使您的代码更可读，并防止出现奇怪的错误
尝试此修订版。在您的示例代码中有一些可疑的东西，如果您的sql语句实际返回了一些东西（也就是说，您正在向它提供正确的数据），这可能会有所帮助：
<?php
require("php/dbc.php");
$temp = mysql_query("SELECT * FROM friends WHERE username = '$username'");
$friends = mysql_fetch_array($temp);
$query = mysql_query("SELECT * FROM user");
while($row = mysql_fetch_array($query)){
if($row['username'] !== $username && in_array($row['username'],$friends) == false){ ?>
<div class="container">
<div class="row">
<div class="col-xs-12 col-sm-6 col-md-6">
<div class="well well-sm">
<div class="row">
<div class="col-sm-6 col-md-4">
</div>
<div class="col-sm-6 col-md-8">
<h4>Name</h4>
<p><i class="glyphicon glyphicon-envelope"></i><?php echo $row['email']; ?>
<br />
<i class="glyphicon glyphicon-gift"></i>bday</p>
<!--
If you have a javascript to run the button, you can use it, otherwise use a form.
<button name="name" value="<?php echo $row['id'];?>" onclick="window.location='whatever.php?id=<?php echo $row['id'];?>'">+1 Add Friend</button>-->
<form id="user<?php echo $row['id'];?>" method="post">
<!-- Since you are doing a lookup on usernames, I presume username here but id (if available) should be used-->
<button name="name" value="<?php echo $row['username'];?>">+1 Add Friend</button>
</form>
</div>
</div>
</div>
</div>
</div><?php }
} ?>