我已经试着弄清楚这一点两天了，我正在遵循youtube教程，为我的Android应用程序进行基本登录，但在此之前，我想测试.php脚本。
我在想，当我按下登录按钮时，我应该会成功，但我得到了无效的凭据，我知道用户名和密码是正确的
下面是我的login.php脚本。
require("config.inc.php");
if (!empty($_POST)) {
//gets user's info based off of a username.
$query = "SELECT id, username, passwrd
FROM application_users
WHERE
username = :username
";
$query_params = array(
':username' => $_POST['username']
);
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one to product JSON data:
$response["success"] = 0;
$response["message"] = "Database Error1. Please Try Again!";
die(json_encode($response));
}
//This will be the variable to determine whether or not the user's information is correct.
//we initialize it as false.
$validated_info = false;
//fetching all the rows from the query
$row = $stmt->fetch();
echo $row;
if ($row) {
//if we encrypted the password, we would unencrypt it here, but in our case we just
//compare the two passwords
if ($_POST['password'] === $row['password']) {
$login_ok = true;
}
}
// If the user logged in successfully, then we send them to the private members-only page
// Otherwise, we display a login failed message and show the login form again
if ($login_ok) {
$response["success"] = 1;
$response["message"] = "Login successful!";
die(json_encode($response));
} else {
$response["success"] = 0;
$response["message"] = "Invalid Credentials!";
die(json_encode($response));
}
} else {
?>
<h1>Login</h1>
<form action="login.php" method="post">
Username:<br />
<input type="text" name="username" placeholder="username" />
<br /><br />
Password:<br />
<input type="password" name="password" placeholder="password" value="" />
<br /><br />
<input type="submit" value="Login" />
</form>
<a href="register.php">Register</a>
</form>
<?php
}？>
因此，当脚本加载并且我从远程MYSQL服务器输入值时，消息将作为无效凭据返回。我只想确保我的登录成功，然后再转到android部分，这本身就是一个很大的待办事项。
我还没有机会用真实的数据库测试它，但这应该可以工作。您仍然需要在文件顶部添加require("config.inc.php");，我已经添加了一个自定义数据库连接。我还使用PDO，所以查询看起来可能与您迄今为止使用的不同。
<?php
// Database connection
try
{
$db = new PDO('mysql:host=localhost;dbname=mydatabase', 'myusername', 'mypassword');
$db->exec('SET CHARACTER SET UTF8');
}
catch (Exception $e)
{
//Message in case of error when connecting to the database
die('Erreur : ' . $e->getMessage());
}
// *** End database connection
$username = ""; // Initialize value in order to keep its value so the user can still see it in his form
if (isset($_POST['login'])) { // if the "login" button is pressed
$username = $_POST['username']; // retrieve username value from the form
$password = $_POST['password']; // retrieve password value from the form
/*
* If a username is unique then a way to do it is to count how many times
* the couple with this username and this password appears in our database.
*/
$query = $db->prepare("SELECT COUNT(*) userAmount ".
"FROM application_users ".
"WHERE username = $username ".
"AND password = $password;");
$query->execute();
$query->closeCursor();
$resultAmount = $query->fetch();
if ($resultAmount['userAmount'] == 0){ // If the couple username-password is unfound
$message = "Username or password unknown";
} else {
$message("Login successful");
}
}
?>
<h1>Login</h1>
<form action="login.php" method="post">
Username:<br />
<input type="text" name="username" placeholder="username" value="<?php echo($username); ?>" />
<br/><br/>
Password:<br/>
<input type="password" name="password" placeholder="password" value="" />
<br/><br/>
<input type="submit" name="login" value="Login" />
<a href="register.php">Register</a>
</form>