我在我的网站上使用PHP邮件表单。我收到的邮件很好，但我收到的标题是a7849972@srv29.000webhost.com，回复地址也是如此。我如何更改我的代码以在标题中获取人员的姓名？我正在使用以下代码：
<?php
if(isset($_POST['submit'])) {
$to = 'chander_info@yahoo.com' ; //put your email address on which you want to receive the information
$subject = 'Message - Contact Form Coast Med Spa'; //set the subject of email.
$headers = 'MIME-Version: 1.0' . "'r'n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "'r'n";
$mailheader = "From: ".$_POST["FirstName"]."'r'n";
$mailheader .= "Reply-To: ".$_POST["email"]."'r'n";
$message = "<table>
<tr><td>Title</td><td>".$_POST['Title']."</td></tr>
<tr><td>First Name</td><td>".$_POST['FirstName']."</td></tr>
<tr><td>Last Name</td><td>".$_POST['LastName']."</td></tr>
<tr><td>E-Mail</td><td>".$_POST['Email']."</td></tr>
<tr><td>Phone Number</td><td>".$_POST['HomePhone']."</td></tr>
<tr><td>Comments</td><td>".$_POST['CAT_Custom_869']."</td></tr>
<tr><td>Contact Method</td><td>".$_POST['CAT_Custom_868']."</td></tr>
<tr><td>Subscribe to: eNewsletter</td> <td>".$_POST['CampaignList_41798']."</td></tr>
</table>" ;
mail($to, $subject, $message, $headers, $mailheader);
header('Location: http://coastlasercenter.com/html/message-contact.html');
echo "Your message has been received";
}
?>
为什么要将头分隔成两个不同的变量？您正在将From和Reply-to标头作为附加参数传递给mail()函数。查看PHP的文档。
试试这个：
<?php
if(isset($_POST['submit'])) {
$to = 'chander_info@yahoo.com' ; //put your email address on which you want to receive the information
$subject = 'Message - Contact Form Coast Med Spa'; //set the subject of email.
$headers = 'MIME-Version: 1.0' . "'r'n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "'r'n";
$headers .= "From: ".$_POST['FirstName']." ".$_POST['LastName']." <".$_POST['Email'].">'r'n";
$headers .= "Reply-To: ".$_POST["email"]."'r'n";
$message = "<table>
<tr><td>Title</td><td>".$_POST['Title']."</td></tr>
<tr><td>First Name</td><td>".$_POST['FirstName']."</td></tr>
<tr><td>Last Name</td><td>".$_POST['LastName']."</td></tr>
<tr><td>E-Mail</td><td>".$_POST['Email']."</td></tr>
<tr><td>Phone Number</td><td>".$_POST['HomePhone']."</td></tr>
<tr><td>Comments</td><td>".$_POST['CAT_Custom_869']."</td></tr>
<tr><td>Contact Method</td><td>".$_POST['CAT_Custom_868']."</td></tr>
<tr><td>Subscribe to: eNewsletter</td> <td>".$_POST['CampaignList_41798']."</td></tr>
</table>" ;
mail($to, $subject, $message, $headers);
header('Location: http://coastlasercenter.com/html/message-contact.html');
echo "Your message has been received";
}
?>
顺便说一句，在将$_POST中的数据连接到电子邮件头之前，您应该考虑验证这些数据，因为这可能会导致电子邮件注入攻击。
在代码中使用类似的格式：
$headers .= "From: ".$userName." <".$userEmailAddress.">";
顺便说一句，您的字符集最好使用utf-8，而不是iso-8859-1。