如何使用json一次发送多条记录？这段代码是我在网上找到的一个示例，但我需要一次发送100个对象或记录。数据来自数据库。
protected String doInBackground(String... args) {
String name = inputName.getText().toString();
String price = inputPrice.getText().toString();
String description = inputDesc.getText().toString();
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("name", name));
params.add(new BasicNameValuePair("price", price));
params.add(new BasicNameValuePair("description", description));
// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_product,
"POST", params);
您必须创建表示对象的JSONObject，并将其添加到Request:
例如，如果你有这样的结构：
｛[｛name："name1"，price:"10"｝，｛name:"name2"，price："15"｝]｝
JSONArray elements=new JSONArray();
JSONObject aux=new JSONObject().put("name", "name1");
aux.put("price", 10);
array.put(aux);
aux=new JSONObject().put("name1", "name2");
aux.put("price", 20);
array.put(aux);
List<NameValuePair> parameters= new ArrayList<NameValuePair>();
parameters.add(new BasicNameValuePair("json", elements.toString()));
HttpPost post = new HttpPost(url);
post.setEntity(new UrlEncodedFormEntity(pairs));
HttpClient cliente = createHttpClient();
return cliente.execute(post);
在服务器中，您可以捕获参数"json"
您可以将数据列表写入String，然后将其发送到php-url。在php json_decode中读取数据列表；
public static class Entity{
private String name;
private String price;
private String description;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPrice() {
return price;
}
public void setPrice(String price) {
this.price = price;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
}
@Test
public void send() throws Exception{
ObjectMapper mapper = new ObjectMapper();
List<Entity> list = new ArrayList<Entity>(); // get the list of Entity;
String json = mapper.writeValueAsString(list); // write list as json
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://url.to.post");
StringEntity entity = new StringEntity(json);
post.setEntity(entity);
HttpResponse response = client.execute(post);
String result = EntityUtils.toString(response.getEntity());
Object responseObject = mapper.readValue(result, Object.class);
}
为了使用ObjectMapper，您需要在库中使用jackson core asl和jackson mapper asl。