寻求使用POST命令传递多个变量的帮助


Looking for assistance with passing multiple variables using POST command

我有以下代码:

                {
                    echo "<tr>";
                    echo "<td>" . $row1['supervisiondate'] . "</td>";
                    echo "<td>" . $row1['level'] . "</td>";
                    echo "<td>" . $row1['division'] . "</td>";
                    echo "<td>" . $row1['supervisor'] . "</td>";
                    echo "<td>" . $row1['totalscore'] . "</td>";
                    echo "<form action='refereesupervision.php' method='post'>";
                    echo "<td>
                    <input name='refereeID' value='" . $row['refereeID'] . "'/>
                    <input name='supervisionID' value='" . $row1['supervisionID'] . "'/>
                    <input type='submit' value='View'/>";
                    echo "</form></td>";
                    echo "</tr>";
                }  </br>

当referesupervisory.php使用post为这两个变量中的每一个接收数据时,只接收refereID。需要注意的是,有两个单独的表的两个单独查询,生成$row和$row1。

寻找一些指导或参考资料来帮助我理解。

干杯

根据注释将输入名称从ID更改为supervisoryID

<input name='ID' value='" . $row1['supervisionID'] . "'/>

<input name='supervisionID' value='" . $row1['supervisionID'] . "'/>

根据评论和编辑原问题。答案是$refereeID$refereeid 不同