intval()不会';似乎不能很好地处理来自shell的信息(正常运行时间)


intval() doesn't seem to work nicely with info from shell (uptime)

我从这里得到的值

$uptime = explode(',', `uptime`);

$uptime[3]load average: 2.26

但是,intval($uptime[3]);返回0

我想这可能是因为小数点的原因,所以我也尝试了这个。

$uptime_days = strpos($uptime[0], ' ');
$uptime_days_value = substr($uptime[0], $uptime_days + 9);
echo intval($uptime_days_value);

$uptime_days_value返回up 60 days,所以intval()应该返回60,但它返回0

如果$uptime[3]是load average: 2.26,那么您将得到0返回,因为load average不是nmber(整数或实数)

$uptime[3] = 'load average: 2.26';
echo intval(explode(': ', $uptime[3])[1]);

如果$uptime_days_valueup 60 days,则intval()将返回0,因为up不是数字

$uptime_days_value = 'up 60 days';
echo intval(explode(' ', $uptime_days_value)[1]);

使用正则表达式

<?php
   $string = "load average: 2.26";
   $expression = "/[0-9]+''.*[0-9]*";
   $matches = array();
   if(preg_match($expression, $string, $matches) != 0) {
      print_r($matches);
   }
 ?>

若有多种类型,则应打印:#或#。#任意位数:

 Array
 (
   [0] => "2.26"
 )

请注意,$matches是通过引用传递的,因此在函数调用中会替换$matchess的现有值。

然后,要获得整数或浮点值:

$number = intval($matches[0]);