从angularJS中抓取一个php-base64图像 - Grabbing a php base64 image from angularJS

Grabbing a php base64 image from angularJS

我正试图从angularJS中获取一个php中的64base编码字符串，但我不太确定我做错了什么。我已经对php运行的makegray.exe写入服务器的图像进行了编码。现在，我正试图获取该图像，并将其返回给angularJS，然后angularJS将其显示给用户。这似乎是一个简单的问题，但我对如何做到这一点感到困惑。

$scope.MakeGray_Button = function(){
    if ($scope.imageUrl) {
        var MakeGray_Form = new FormData();
        MakeGray_Form.append("FileName", $scope.imageUrl);
        $http({
        method : "POST",
        url    : "../opencv/MakeGray/MakeGray.php",
        data   : MakeGray_Form,
        transformRequest: angular.identity,
        headers: {'Content-Type': undefined}
        }).
        success(function(){                     
           // some magic code here that grabs the $base64 variable from php
        })
        .error(function(){});
    }
    else{
        alert("Please upload an image");
    }
}

php

<?php
$imgname = $_POST["FileName"];
$inputDir = "../../uploads/" . $imgname;
$outputDir = "../../processed/" . $imgname;
$MakeGray = "./makegray " . $inputDir . " " . $outputDir;
$runExec  = exec($MakeGray, $out);
$type = pathinfo($outputDir, PATHINFO_EXTENSION);
$data = file_get_contents($outputDir);
$base64 = 'data:image/' . $type . ';base64,' . base64_encode($data);
echo "$base64";
?>

$scope.MakeGray_Button = function(){
    if ($scope.imageUrl) {
        var MakeGray_Form = new FormData();
        MakeGray_Form.append("FileName", $scope.imageUrl);
        $http({
        method : "POST",
        url    : "../opencv/MakeGray/MakeGray.php",
        data   : MakeGray_Form,
        transformRequest: angular.identity,
        headers: {'Content-Type': undefined}
        }).then(function(response){                     
           //response object should hold your base64 image data.
           //you can change src of an img tag with ng-src and let the browser render your image.
        },function(response){});
    }
    else{
        alert("Please upload an image");
    }
}

首先使用.then()来代替不推荐使用的函数.success()和.error()

则也如上述代码中那样捕获CCD_ 4。

您可以通过将base64图像作为img标记的src来轻松地渲染它。ng-src应该对此有所帮助。

如果您希望图像为字符串，则应改为选中response对象。

好的，我开始工作了。。。

$scope.MakeGray_Button = function(){
    if ($scope.imageUrl) {
        var MakeGray_Form = new FormData();
        MakeGray_Form.append("FileName", $scope.imageUrl);
        $http({
        method : "POST",
        url    : "../opencv/MakeGray/MakeGray.php",
        data   : MakeGray_Form,
        transformRequest: angular.identity,
        headers: {'Content-Type': undefined}
        }).
        success(function(data){                     
           $scope.data = data;
           base64 = data;
           $("#img2").prop("src", base64);
        })
        .error(function(){});
    }
    else{
        alert("Please upload an image");
    }
}

希望这能帮助其他试图使用base64编码字符串从php向JS显示图像的人！